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SVETLANKA909090 [29]
4 years ago
6

If the diameter of the circle is above 20mm what is the area

Mathematics
2 answers:
LekaFEV [45]4 years ago
8 0
A≈3.14×10-4m² there you go!!!
mart [117]4 years ago
3 0

Answer:

The area of the circle is 314mm²

Step-by-step explanation:

To solve this problem we have to use the formula for calculating the area of a circle

a = area

π = 3.14

r = radius

d = diameter

r = d/2

r = 20mm / 2

r = 10mm

a = π * r²

we replace the known values

a = 3.14 * (10mm)²

a = 3.14 * 100mm²

a = 314mm²

The area of the circle is 314mm²

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andreyandreev [35.5K]

Answer:

1. 1/5

Step-by-step explanation:

The question is basically asking what each "y" is being multiplied to get the next "y".

2*1/5=2/5

2/5*1/5=2/25

2/25*1/5=2/125

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3 years ago
Triangles...................
stepan [7]

Answer:

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In a random sample of 200 Americans, 51% said they favor building more nuclear power plants. In a random sample of 150 French, 4
Varvara68 [4.7K]

Answer:

Yes, there is enough evidence to say the proportions are the same.

Step-by-step explanation:

Null hypothesis: The proportions are the same.

Alternate hypothesis: The proportions are not the same.

Data given:

p1 = 51% = 0.51

n1 = 200

p2 = 48% = 0.48

n2 = 150

pooled proportion (p) = (n1p1 + n2p2) ÷ (n1 + n2) = (200×0.51 + 150×0.48) ÷ (200 + 150) = 174 ÷ 350 = 0.497

Test statistic (z) = (p1 - p2) ÷ sqrt[p(1-p)(1/n1 + 1/n2) = (0.51 - 0.48) ÷ sqrt[0.497(1-0.497)(1/200 + 1/150)] = 0.03 ÷ 0.054 = 0.556

The test is a two-tailed test. At 0.10 significance level the critical values -1.645 and 1.645

Conclusion:

Fail to reject the null hypothesis because the test statistic 0.556 falls within the region bounded by the critical values.

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3 years ago
2. P337. 23. A large box contains 10,000 ball bearings. A random sample of 120 is chosen. The sample mean diameter is 10 mm, and
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Answer:

B is True

A, C. D are false

Step-by-step explanation:

Given :

Sample size, n = 120

Mean diameter, m = 10

Standard deviation, s = 0.24

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The confidence interval represents how the true mean value compares to a set of values around the mean computed from a set of sample drawn from the population.

The population here is N = 10000

To obtain

Confidence interval (C. I) :

Mean ± margin of error

Margin of Error = Zcritical * s/sqrt(n)

Margin of Error = 1.96 * 0.24/sqrt(120)

Confidence interval for the 10,000 ball bearing :

10 ± 1.96 * (0.24) / sqrt(120)

Hence. The confidence interval defined as :

10 ± 1.96 * (0.24) / sqrt(120) is the 95% confidence interval for the mean diameter of the 10,000 bearings in the box.

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