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TiliK225 [7]
3 years ago
8

True or false weight is a measurement of force

Mathematics
1 answer:
expeople1 [14]3 years ago
7 0

Answer:

True I hope this helps Have a great day.

The weight of an object is a measure of the force exerted on the object by gravity, or the force needed to support it.

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Eddie drilled into a piece of wood and I joist to attach them if he drilled 3 inches in the wood was one and 1 1/3 inches thick
NARA [144]
Let JD = Distance drilled in joist 
<span>JD = 3 - 1 1/3 </span>
<span>JD = 9/3 - 4/3 </span>
<span>========================== </span>
<span>JD = 5/3 or 1 2/3 in ◄ Ans 

Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.

</span>
7 0
3 years ago
25 + 8 (7y - 3) + 3y
nasty-shy [4]

Answer:

59y+1

Step-by-step explanation:

25 + 8 (7y - 3) + 3y

Distribute

25+56y-24+3y

Combine like terms

59y+1

7 0
3 years ago
A square fits exactly inside a circle with each of its vertices being on the circumference of the circle.
swat32

Answer:

The side of the square is 5.971 cm

Step-by-step explanation:

If the square fits the circle exactly, then its diagonal is equal to the diameter of the circle. Since the side of the square has a length of x cm, then it's diagonal have the length of x\sqrt2 cm. Using the circle's area we can find the diagonal of the square, as shown below:

area = \pi*r^2\\56 = pi*r^2\\r^2 = \frac{56}{\pi}\\r = \sqrt{\frac{56}{\pi}}\\r = 4.222

Since the diameter of the circle is the same as the diagonal of the square, then:

x\sqrt{2} = 2*r \\x = \frac{2*r}{\sqrt{2}}\\x = \frac{2*4.222}{\sqrt{2}}\\x = 5.971

The side of the square is 5.971 cm

8 0
3 years ago
Read 2 more answers
Please help me! I'm spending 50 points on this question and my last two questions never even got answered!
Verdich [7]

Answer:

C.

Step-by-step explanation:

Domain is only affected if certain values can make the result something that either doesn't make sense or is an error. In your situation, it wants you to find the domain of f/g, which is a fraction. The only rule we have for fractions regarding domain is that we simply can't divide by zero, to find the domain for any fraction with variables in the denominator, what I do is take the denominator, set it equal to 0, and solve for x.

So, if we're taking f/g, we have:

\frac{3x^2 + x^4 + 2}{4x - 3}

4x - 3 makes up our denominator, the bottom part of the fraction. So

4x - 3 = 0

4x = 3

x = 3/4

So the denominator is equal to zero when x is equal to 3/4. This would produce an error in any calculator because you can't divide by zero. The domain here is all real numbers except for 3/4.

(For future problems, the only thing to look out for is if your numerator, the top part of the fraction, factors into something that cancels with the bottom. In that case, it wouldn't affect domain because you aren't actually dividing by anything. For example:

\frac{x^2 - 4}{x-2}

If we factor the top, we see that x^2 - 4 = (x - 2)(x + 2). In this case, we have (x - 2) in both the top and bottom of the fraction, so it cancels out, and from there nothing else is restricting our domain. It would be all real numbers in a case like that.)

8 0
3 years ago
Given G (1,2) and K(8,12) what does it mean to find the point P on line GK such that 3 (GP) = 2 (PK)?
Lunna [17]
Check the picture below.

3 0
3 years ago
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