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Sergio039 [100]
3 years ago
5

What is the maximum theoretical efficiency possible for a heat engine operating between a reservoir in which ice and water coexi

st, and a reservoir in which water and steam coexist? The pressure is constant at 1.0 atmosphere for both reservoirs.
Chemistry
1 answer:
Tju [1.3M]3 years ago
6 0

Answer:

\eta_{th} = 26.8\,\%

Explanation:

The maximum theoretical efficiency for a heat engine is given by the Carnot's Cycle. The temperatures of the hot reservoir and the cold reservoir at 1.0 atmosphere are 373.15 K and 273.15 K, respectively. Then:

\eta_{th} = \left(1 - \frac{T_{L}}{T_{H}}  \right)\times 100\,\%

\eta_{th} = \left(1-\frac{273.15\,K}{373.15\,K}  \right)\times 100\,\%

\eta_{th} = 26.8\,\%

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(In attachment)

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Ca(OH)2(aq) + 2HCl(aq)------> CaCl2(aq) + 2H2O(l) ΔH-?

CaO(s) + 2HCl(aq)-----> CaCl2(aq) + H2O(l),  Δ<span>H = -186 kJ
</span>
CaO(s) + H2O(l) -----> Ca(OH)2(s), Δ<span>H = -65.1 kJ
</span>
1) Ca(OH)2 should be  reactant, so
CaO(s) + H2O(l) -----> Ca(OH)2(s) 
we are going to take as 
 Ca(OH)2(s)---->CaO(s) + H2O(l), and ΔH = 65.1 kJ

2) Add 2 following equations
Ca(OH)2(s)---->CaO(s) + H2O(l),                    and ΔH = 65.1 kJ
<span><u>CaO(s) + 2HCl(aq)-----> CaCl2(aq) + H2O(l), and ΔH = -186 kJ</u>

</span>Ca(OH)2(s)+CaO(s) + 2HCl(aq)--->CaO(s) + H2O(l)+CaCl2(aq) + H2O(l)

Ca(OH)2(s)+ 2HCl(aq)---> H2O(l)+CaCl2(aq) + H2O(l)
By addig these 2 equation, we got the equation that we are needed,
so to find enthalpy of the reaction, we need to add  enthalpies of reactions we added.
ΔH=65.1 - 186 ≈ -121 kJ
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3 years ago
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