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Sergio039 [100]
3 years ago
5

What is the maximum theoretical efficiency possible for a heat engine operating between a reservoir in which ice and water coexi

st, and a reservoir in which water and steam coexist? The pressure is constant at 1.0 atmosphere for both reservoirs.
Chemistry
1 answer:
Tju [1.3M]3 years ago
6 0

Answer:

\eta_{th} = 26.8\,\%

Explanation:

The maximum theoretical efficiency for a heat engine is given by the Carnot's Cycle. The temperatures of the hot reservoir and the cold reservoir at 1.0 atmosphere are 373.15 K and 273.15 K, respectively. Then:

\eta_{th} = \left(1 - \frac{T_{L}}{T_{H}}  \right)\times 100\,\%

\eta_{th} = \left(1-\frac{273.15\,K}{373.15\,K}  \right)\times 100\,\%

\eta_{th} = 26.8\,\%

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Calculate the weight of 5 atoms of Mg.​
kumpel [21]

Answer:

2.0179701e-22

Explanation:

8 0
3 years ago
35.5 moles of lithium fluoride is dissolved in 65 L of solution
kkurt [141]

Answer:

Explanation:

L

=

1.10

L

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Explanation:

The Molarity

M

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M

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m

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l

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For this question we are given the Molarity 0.88M

We are told the solute is a 25.2 gram sample of LiF, Lithium Fluoride

We can convert the mass of LiF to moles by dividing by the molar mass of LiF

Li = 6.94

F = 19.0

LiF = 25.94 g/mole

25.2

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x

1

m

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l

25.94

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s

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0.97

moles

Now we can take the the molarity and the moles and calculate the Liters of solution

M

=

m

o

l

L

M

L

=

m

o

l

L

=

m

o

l

M

L

=

0.97

m

o

l

0.88

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L

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1.10

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of solution i just did look at my papaer

3 0
4 years ago
Can you please help me and can you show your work please
natali 33 [55]

Answer:

1. 25 moles water.

2. 41.2 grams of sodium hydroxide.

3. 0.25 grams of sugar.

4. 340.6 grams of ammonia.

5. 4.5x10²³ molecules of sulfur dioxide.

Explanation:

Hello!

In this case, since the mole-mass-particles relationships are studied by considering the Avogadro's number for the formula units and the molar mass for the mass of one mole of substance, we proceed as shown below:

1. Here, we use the Avogadro's number to obtain the moles in the given molecules of water:

1.5x10^{25}molecules*\frac{1mol}{6.022x10^{23}molecules} =25 molH_2O

2. Here, since the molar mass of NaOH is 40.00 g/mol, we obtain:

1.2mol*\frac{40.00g}{1mol} =41.2g

3. Here, since the molar mass of C6H12O6 is 180.15 g/mol:

45g*\frac{1mol}{180.15g}=0.25g

4. Here, since the molar mass of ammonia is 17.03 g/mol:

20mol*\frac{17.03g}{1mol}=340.6g

5. Here, since the molar mass of SO2 is 64.06 g/mol:

48g*\frac{1mol}{64.06g} *\frac{6.022x10^{23}molecules}{1mol} =4.5x10^{23}molecules

Best regards!

5 0
3 years ago
Breaking a solid reactant into pieces results in
Hitman42 [59]

Answer:

If one of the reactants is a solid, only the particles at the surface can partake in the reaction. Breaking the reactant into smaller pieces increases the surface and more particles are exposed to the reaction mixture. This results in an increased frequency of collisions and therefore a faster rate of reaction

6 0
3 years ago
Using the balanced equation given below, calculate the number of moles of CaBr2 produced in the reaction of 5.0 moles of AlBr3.
allochka39001 [22]

Answer:

7.5 moles of CaBr2 are produced

Explanation:

Based on the equation:

2AlBr3 + 3CaO → Al2O3 + 3CaBr2

<em>2 moles of AlBr3 produce 3 moles of CaBr2 if CaO is in excess.</em>

<em />

Using this ratio: 2 moles AlBr3 / 3 moles CaBr2. 5 moles of AlBr3 produce:

5 moles AlBr3 * (3 moles CaBr2 / 2 moles AlBr3) =

<h3>7.5 moles of CaBr2 are produced</h3>

<em />

4 0
3 years ago
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