Answer:
5.1563867 × 10-9 miles
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Potassium hexacyanochromate(III)
A systematic name is a name given in a systematic way to a
chemical substance, out of a definite collection.
The systematic name for the coordination compound k3 cr(cn)6
is Potassium hexacyanochromate(III). This compound contains potassium (k3), six
cn which is called hexacyano, and cr (chromium).
Answer:
There is 541.6 grams of calcium carbonate produced from 5.11 moles
Explanation:
Step 1: Data given
Number of moles of sodium carbonate ( Na2CO3) = 5.11 moles
Molar mass of sodium Carbonate:
⇒ Molar mass of Sodium = 22.99 g/mole
⇒ Molar mass of Carbon = 12.01 g/mole
⇒ Molar mass of Oxygen = 16 g/mole
Molar mass of Na2CO3 = 2* 22.99 + 12.01 + 3*16 = 105.99 g/mole
Step 2: Calculate mass of 5.11 moles of sodium carbonate
mass = number of moles of sodium carbonate * Molar mass of sodium carbonate
mass = 5.11 moles * 105.99 g/moles = 541.6 grams ≈ 542 grams
There is 541.6 grams of calcium carbonate produced from 5.11 moles Na2CO3
The hybridization of the central atom in SCl₂ is sp³.
<h3>What is Lewis Structure ? </h3>
Lewis structure is also known as Lewis dot structure which simply represent the valence electron of an atom.
<h3>What is Hybridization ? </h3>
Hybridization is defined as the mixing of two atomic orbitals belongs to same atom but having entirely different shapes , energies which produces a new hybridized orbitals.
Now first write the electronic configuration of central atom.
The central atom in SCl₂ is S (Sulphur).
Electronic configuration of S: [Ne] 3s² 3p⁴
One 3s and three 3p undergo hybridization to form sp³ orbitals. Here each atom forms bond with one sp³ hybrid orbital.
Thus from the above conclusion we can say that The hybridization of the central atom in SCl₂ is sp³.
Learn more about the Hybridization here: brainly.com/question/24180903
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Answer:
First you'll need to divide the mass of K2Cr2O7 by its molar mass and volume which should be easy but I'll do some of it to help you out
Explanation:



and


so that's the mass of K2Cr2O7 and then you divide it by the molar mass and volume.
Hopefully you can do that on your own! Hope I helped a bit atleast and I have a good feeling about 0.438 but I don't want you to just guess