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gladu [14]
3 years ago
8

How do you factor quadratics trinomials

Mathematics
1 answer:
Doss [256]3 years ago
6 0

You can factor trinomials by taking factors of the lead term (x^2) and using them in the front of a set of parenthesis. For instance, if you had 2x^2 as the first term, you would use (2x _____)(x______).

Now to find what goes at the end of the parenthesis, you take factors of the last number. Say our last number was -5, we could use -5 and 1 or 5 and -1. For the purpose of this, we'll use -5 and 1. This would give us (2x - 5)(x + 1).

Now, to be sure you've selected the right ones, you would multiply the two parenthesis together and see if the middle term matches the original equation.

(2x - 5)(x + 1)

2x^2 - 5x + 2x - 5

2x^2 - 3x - 5

So you'll notice that the middle term is -3. If this wasn't the original, you could try those numbers in a different order until you get the correct middle term.

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Simplify the expression ​
finlep [7]

Answer:

\frac{2*x - 2}{2*x}  - \frac{3*x + 2}{4*x} = \frac{x - 6}{4*x}

Step-by-step explanation:

We have the expression:

\frac{2*x - 2}{2*x}  - \frac{3*x + 2}{4*x}

The first thing we want to do, is to have the same denominator in both equations, then we need to multiply the first term by (2/2), so the denominator becomes 4*x

We will get:

(\frac{2}{2} )\frac{2*x - 2}{2*x}  - \frac{3*x + 2}{4*x} = \frac{4*x - 4}{4*x}  - \frac{3*x + 2}{4*x}

Now we can directly add the terms to get:

\frac{4*x - 4}{4*x}  - \frac{3*x + 2}{4*x} = \frac{4*x - 4 - 3*x - 2}{4*x}  = \frac{x - 6}{4*x}

We can't simplify this anymore

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3 years ago
Is F=((x,y) | x+y=10 a function or a relation
asambeis [7]

that is a function man

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4 years ago
Mel slides down waterslide A, and Victor slides down waterslide B. After 2 seconds, Mel was 50 feet in the air, and after 5 seco
iren [92.7K]
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3 years ago
6+q=1 <br> Help I forgot how to do these.
Helga [31]

Answer:

q=-5

Step-by-step explanation:

6+q=1

Isolate the variable by subtracting 6 from both sides of the equation

q=1-6

q=-5

4 0
3 years ago
Read 2 more answers
Can someone pls help me?
Alexxandr [17]
Your answer is 2,401
8 0
3 years ago
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