Answer: 6x
Work Shown:
For each step, the logs are all base b. This is to save time and hassle of writing tricky notation of having to write the smaller subscript 'b' multiple times. The first rule to use is that log(x^y) = y*log(x) for any base of a logarithm. The second rule is that meaning that the log base of itself is 1
log(b^(6x)) = 6x*log(b) .... pull down exponent using the first rule above
log(b^(6x)) = 6x*1 .... use the second rule mentioned
log(b^(6x)) = 6x
Answer:
D
Step-by-step explanation:
Given a square with vertices at points (2,1), (1,2), (2,3) and (3,2).
Consider option A.
1st transformation will map vertices of the square into points
2nd transformation = reflection over y = 1 has the rule (x,2-y). So,
These points are exactly the vertices of the initial square.
Consider option B.
1st transformation will map vertices of the square into points
2nd transformation = reflection over x = 3 has the rule (6-x,y). So,
These points are exactly the vertices of the initial square.
Consider option C.
1st transformation will map vertices of the square into points
2nd transformation = reflection over y = -x + 7 will map vertices into points
These points are exactly the vertices of the initial square.
Consider option D.
1st transformation will map vertices of the square into points
2nd transformation = reflection over y = -x + 2 will map vertices into points
These points are not the vertices of the initial square.
Answer:
The roots are , which is given by option C.
Step-by-step explanation:
Solving a quadratic equation:
Given a second order polynomial expressed by the following equation:
.
This polynomial has roots such that
, given by the following formulas:
In this question, we have that:
Which is a quadratic equation with . So
So the roots are , which is given by option C.