45°. I’m not sure what the relationship is but I think it’s linear pair ?
Answer:
a) 0.59871
b) 0.22663
e) 0.95994
Step-by-step explanation:
The height of adult males on a given South Pacific Island is approximately normally distributed with mean 65 inches and standard deviation of 4 inches.
We solve using z score
z = (x-μ)/σ, where
x is the raw score
μ is the population mean = 65 inches
σ is the population standard deviation = 4 inches
a). Taller than 64 inches
This means x > 64
Hence,
64 - 65/4
=- 1/4 = -0.25
P-value from Z-Table:
P(x<64) = 0.40129
P(x>64) = 1 - P(x<64) = 0.59871
b.) shorter than 62 inches
Hence,
62 - 65/4
=- 3/4 =- 0.75
P-value from Z-Table:
P(x<62) = 0.22663
c.) between 64 inches and 68 inches
Hence,
for 64 inches
64 - 65/4
=- 1/4 = -0.25
P-value from Z-Table:
P(x = 64) = 0.40129
For 68 inches
Hence,
68 - 65/4
= 3/4= 0.75
P-value from Z-Table:
P(x = 68) = 0.77337
d.) between 58 and 68 inches
e.) taller than 58 inches
Hence,
58 - 65/4
= -6/4 = -1.5
P-value from Z-Table:
P(x<58) = 0.040059
P(x>58) = 1 - P(x<58) = 0.95994
The value of 3 would be 3,000.
Why thousands? Well because u have to count from the right, then back, so ones, tens, hundreds, then thousands lands on 3 so hope this helps.
Let X = the 29% alloy and Y = the 60% alloy.
They want a total of 80kg, so you have X +Y = 80
Rewrite that to get X = 80-Y
You also want 0.20X + 0.60Y = 0.52(80)
Replace X with 80-y:
0.20(80-y) + 0.60y = 0.52(80)
Simplify:
16 - 0.20y + 0.60y = 41.6
Combine like terms:
16 +0.40y = 41.6
Subtract 16 from each side:
0.40y = 25.6
Divide both sides by 0.40
y = 25.6 / 0.40
y = 64
Now you have Y replace y with 80 in X = 80-Y
X = 80 - 64
X = 16
They need 64 Kg of the 60% alloy and 16 Kg of the 20% alloy.
um I dunno because I need points to ask a question sorry
