Can any experts help me?? Solve for x° and y°. Easy for anyone.

fredd [130]

Hey there! :D

We are basically trying to find fractions that equal each other.

3/12= 1/4 4/16= 1/4

The first option applies.

5/8= 5/8 (simplest form) 8/15= 8/15 (simplest form)

The second does not apply.

1/6= 1/6 (simplest form) 5/30= 1/6

The third option does apply.

18/12= 3/2 3/2=3/2 (simplest form)

The fourth option does apply.

The first, third, and fourth option are the answers.

I hope this helps!
~kaikers

7 0

3 years ago

Read 2 more answers

How many squares to shade

slamgirl [31]

You got to shade five squares

6 0

3 years ago

A-One Talent Agency has 108 clients. 42 of the clients play piano and 51 of the clients play guitar.

Butoxors [25]

Thwre are 28 clients who don not play any of the instrument using the principle of Venn distribution.

Using a Venn diagram analogy :

Total number of client, U = 108
Piano, P = 42
Guitar, G = 51
Piano and Guitar, (PnG) = 13
None =?

From the information given :

P only = 42 - 13 = 29
G only = 51 - 13 = 38

The total number of clients can be related thus :

Total = P only + G only + PnG + None

108 = 29 + 38 + 13 + None

108 = 80 + None

None = 108 - 80

None = 28

Therefore, the number of clients who do not play any of the instruments is 28

Learn more :brainly.com/question/12570490

7 0

3 years ago

Help ASAP

CaHeK987 [17]

About 3.7 inches. Look at the 12 on the x axis because that is one year and see where it hits the line

6 0

2 years ago

A researcher has two percentages and wants to know if the percentages are statistically different. The researcher calculates the

love history [14]

Answer:

$p_v =2*P(Z>4.21) =2.55x10^{-5}$

And we can use the following excel code to find it:"=2*(1-NORM.DIST(4.21,0,1,TRUE)) "

With the p value obtained and using the significance level assumed for example $\alpha=0.05$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the percentage 1 is significantly different from the percentage 2.

D) Are statistically different.

Step-by-step explanation:

The system of hypothesis on this case are:

Null hypothesis: $\mu_1 = \mu_2$

Alternative hypothesis: $\mu_1 \neq \mu_2$

Or equivalently:

Null hypothesis: $\mu_1 - \mu_2 = 0$

Alternative hypothesis: $\mu_1 -\mu_2\neq 0$

Where $\mu_1$ and $\mu_2$ represent the percentages that we want to test on this case.

The statistic calculated is on this case was Z=4.21. Since we are conducting a two tailed test the p value can be founded on this way.

$p_v =2*P(Z>4.21) =2.55x10^{-5}$

And we can use the following excel code to find it:"=2*(1-NORM.DIST(4.21,0,1,TRUE)) "

With the p value obtained and using the significance level assumed for example $\alpha=0.05$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the percentage 1 is significantly different from the percentage 2.

And the best option on this case would be:

D) Are statistically different.

4 0

3 years ago