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zimovet [89]
3 years ago
5

Probability played a role in the rigging of the April 24, 1980, Pennsylvania state lottery. To determine each digit of the three

-digit winning number, each of the numbers 0, 1, 2, , 9 was written on a Ping-Pong ball, the 10 balls were blown into a compartment, and the number selected for the digit was the one on the ball that floats to the top of the machine. To alter the odds, the conspirators injected a liquid into all balls used in the game except those numbered 4 and 6, making it almost certain that the lighter balls would be selected and determine the digits in the winning number. They then proceeded to buy lottery tickets bearing the potential winning numbers. How many potential winning numbers were there (666 was the eventual winner)?
Mathematics
1 answer:
Whitepunk [10]3 years ago
7 0

Answer:

8 potential winners ( 444, 446, 644, 464, 466, 646, 664, 666)

Step-by-step explanation:

To alter the odds the balls numbered 4 and 6 werent injected with liquid and hence they will float making it certain for their selection and determination as the winning digits. The potential of the winning numbers are (2)^3=8.

Since 4 and 6 ain't filled with liquid, they would be selected and determine the digits in the winning numbers in 8 ways ( 444, 446, 644, 464, 466, 646, 664, 666). The potential winning number is among them.

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Helpppp! I have no idea what to do..
tatiyna

Answer:

For number 3 the answer is vertical angels are congruent.

For number 4 the answer is Reflexive property.

And for number 5 i believe the answer would be Angle Side Angel

Step-by-step explanation:

i hope this helps

3 0
3 years ago
∆ ABC is similar to ∆DEF and their areas are respectively 64cm² and 121cm². If EF = 15.4cm then find BC.​
lyudmila [28]

{\large{\textsf{\textbf{\underline{\underline{Given :}}}}}}

★ ∆ ABC is similar to ∆DEF

★ Area of triangle ABC = 64cm²

★ Area of triangle DEF = 121cm²

★ Side EF = 15.4 cm

{\large{\textsf{\textbf{\underline{\underline{To \: Find :}}}}}}

★ Side BC

{\large{\textsf{\textbf{\underline{\underline{Solution :}}}}}}

Since, ∆ ABC is similar to ∆DEF

[ Whenever two traingles are similar, the ratio of the areas of two similar triangles is equal to the square of the ratio of their corresponding sides. ]

\therefore \tt \boxed{  \tt \dfrac{area( \triangle \: ABC )}{area( \triangle \: DEF)} =  { \bigg(\frac{BC}{EF} \bigg)}^{2}   }

❍ <u>Putting the</u><u> values</u>, [Given by the question]

• Area of triangle ABC = 64cm²

• Area of triangle DEF = 121cm²

• Side EF = 15.4 cm

\implies  \tt  \dfrac{64   \: {cm}^{2} }{12 \:  {cm}^{2} }  =  { \bigg( \dfrac{BC}{15.4 \: cm} \bigg) }^{2}

❍ <u>By solving we get,</u>

\implies  \tt    \sqrt{\dfrac{{64 \: cm}^{2} }{ 121 \: {cm}^{2} }}   =   \bigg( \dfrac{BC}{15.4 \: cm} \bigg)

\implies  \tt    \sqrt{\dfrac{{(8 \: cm)}^{2} }{  {(11 \: cm)}^{2} }}   =   \bigg( \dfrac{BC}{15.4 \: cm} \bigg)

\implies  \tt    \dfrac{8 \: cm}{11 \: cm}    =   \dfrac{BC}{15.4 \: cm}

\implies  \tt    \dfrac{8  \: cm \times 15.4 \: cm}{11 \: cm}    =   BC

\implies  \tt    \dfrac{123.2 }{11 } cm   =   BC

\implies  \tt   \purple{  11.2 \:  cm}   =   BC

<u>Hence, BC = 11.2 cm.</u>

{\large{\textsf{\textbf{\underline{\underline{Note :}}}}}}

★ Figure in attachment.

\rule{280pt}{2pt}

4 0
2 years ago
What is the probability of rolling an even number with one roll of a number cube?<br>​
oee [108]

Answer:

50% or 1/2

Step-by-step explanation:

There is an even amount of even and odd numbers on a number cube, therefor it is split half and half, giving you 50%.

3 0
3 years ago
An olympic hurdler accelerates at a rate of 15.5 m/s2 . what is the rate in miles/min2 ? 1. 6.89 miles/min2 2. 31.8 miles/min2 3
Tom [10]
For this case we have to take into account the following conversions:
 1 mile = 1609.34 meters&#10;&#10;1 minute = 60 seconds
 Let's first transform the expression to miles per seconds squared:
 (15.5) * (1 / 1609.34) = 0.009631277 mi / s ^ 2&#10;
 Then, we transform the result to miles per minute squared.
 We have then:
 (0.009631277) * (60) ^ 2 = 34.7 mi / min ^ 2&#10;
 Answer:
 
the rate in miles/min^2 is:
 
34.7 mi / min ^ 2
3 0
3 years ago
26) Write the equation of the circle with center (0, 0) and (3, 6) a point on the circle. A) x2 + y2 = 9 B) x2 + y2 = 30 C) x2 +
alexdok [17]

Answer:C) x2 + y2 =45

Step-by-step explanation:

The equation of a circle in standard form is (x-h)2+(y-k)2=r2.

Since you know the center is (0,0), you can sub this is value in for h and k, then use the point (3,6) to sub in for x and y and you will find r2 =45. Hope that helps :)

4 0
3 years ago
Read 2 more answers
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