Circle Q is centered at the origin with radius r. Point P(x, y) lies on circle Q. Make a conjecture. How can you find an equatio
n relating the radius to the coordinates of point P? Check all that apply. Notice that ΔPQS forms a right triangle.
Because ΔPQS is a right triangle,
apply the Pythagorean theorem.
x² + y² = r²
2 answers:
Answer:
x2=y2=r2
Step-by-step explanation:
edge
Answer:
The relation
is explained below.
Step-by-step explanation:
P(x, y) is a point on the circle. Q is the origin. Join PQ.
PQ is the radius.
Therefore, PQ = r
Draw PS perpendicular to the x-axis.
Now, ΔPQS is a right triangle.
By Pythagoros theorem,



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