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zhannawk [14.2K]
2 years ago
8

Solve for x.

Mathematics
1 answer:
Tamiku [17]2 years ago
5 0
The answer to the question is a

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Shirley got 72% on a Chemistry exam. The test was marked out of 150.
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Answer:

Nhjj

Step-by-step explanation:

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Which of the following best describes a three-dimensional solid made from a pile of similar circles that grow smaller as the sol
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Your answer is D) Cone
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The Laplace Transform of a function f(t), which is defined for all t > 0, is denoted by L{f(t)} and is defined by the imprope
lesya692 [45]

(1) D

L_s\left\{t\right\} = \displaystyle\int_0^\infty te^{-st}\,\mathrm dt

Integrate by parts, taking

u = t \implies \mathrm du=\mathrm dt

\mathrm dv = e^{-st}\,\mathrm dt \implies v=-\dfrac1se^{-st}

Then

L_s\left\{t\right\} = \displaystyle \left[-\frac1ste^{-st}\right]\bigg|_{t=0}^{t\to\infty}+\frac1s\int_0^\infty e^{-st}\,\mathrm dt

L_s\left\{t\right\} = \displaystyle \frac1s\int_0^\infty e^{-st}\,\mathrm dt

L_s\left\{t\right\} = \displaystyle -\frac1{s^2}e^{-st}\bigg|_{t=0}^{t\to\infty}

L_s\left\{t\right\} = \displaystyle \boxed{\frac1{s^2}}

(2) A

L_s\left\{1\right\} = \displaystyle\int_0^\infty e^{-st}\,\mathrm dt

L_s\left\{1\right\} = \displaystyle\left[-\frac1se^{-st}\right]\bigg|_{t=0}^{t\to\infty}

L_s\left\{1\right\} = \displaystyle\boxed{\frac1s}

7 0
3 years ago
Consider the equation x^2=36 which of the statements below are true
pentagon [3]
Given:

the equation x^2 = 36

Let us evaluate the equation. This equation is a quadratic equation. The roots of this equation are +6 and -6. 

To determine the roots of the equation, solve:

x^2 = 36

x = +6
x = -6
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If -3 + i is a root of the polynomial function f(x), which of the following must also be a root of f(x)?
VashaNatasha [74]

Step-by-step explanation:

3 - 1

answer

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