2 years ago

Solve for x.

1 answer:

5 0

The answer to the question is a

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chubhunter [2.5K]

But where is the diagram?

5 0

3 years ago

IceJOKER [234]

Hi there!

$\large\boxed{f^{-1}(x) = \sqrt[3]{\frac{x+4}{9} } }$

$f(x) = 9x^{3} - 4$

Find the inverse by replacing f(x) with y and swapping the x and y variables:

$x = 9y^{3} - 4$

Isolate y by adding 4 to both sides:

$x + 4 = 9y^{3}$

Divide both sides by 9:

$\frac{x+4}{9}= y^{3}$

Take the cube root of both sides:

$y = \sqrt[3]{\frac{x+4}{9} }\\\\f^{-1}(x) = \sqrt[3]{\frac{x+4}{9} }$

7 0

3 years ago

Zinaida [17]

Answer:

it is a relationship where the first difference is equal and the second difference is 0

3 0

2 years ago

Radda [10]

A because one input can have only one output

3 0

3 years ago

baherus [9]

Do you still need help with it I can help you?

5 0

2 years ago