In triangle ABC, angle A is a right angle and m angle B =45 degrees

When truckers are on long-haul drives, their driving logs must reflect their average speed. Average speed is the total distance

bekas [8.4K]

a) $v=\frac{d_{tot}}{t_{tot}}=\frac{(3 h)(60 mph)+20 mi}{3 h +t_2}$

The average speed is equal to the ratio between the total distance ( $d_{tot}$ and the total time taken ( $t_{tot}$ ):

$v=\frac{d_{tot}}{t_{tot}}$

the distance travelled by the trucker in the first 3 hour can be written as the time multiplied by the velocity:

$d_1 = (3 h)(60 mph)=180 mi$

So the total distance is

$d_{tot}=d_1 +d_2 = 180 mi+20 mi=200 mi$

The total time is equal to the first 3 hours + the time taken to cover the following 20 miles in the city:

$t_{tot}=3 h +t_2$

So, the equation can be rewritten as:

$v=\frac{d_{tot}}{t_{tot}}=\frac{(3 h)(60 mph)+20 mi}{3 h +t_2}$

b) 0.50 h (half a hour)

Since we know the value of the average speed, $v=57.14 mph$ , we can substitute it into the previous equation to find the value of $t_2$ , the time the trucker drove in the city:

$v=\frac{200 mi}{3h +t_2}\\3h+t_2 = \frac{200 mi}{v}\\t_2 = \frac{200 mi}{v}-3h=\frac{200 mi}{57.14 mph}-3 h=0.50 h$

3 0

3 years ago

What is the greatest common factor of 9x^{2}y9x 2 y and 5x^{4}y^{2}5x 4 y 2 ?

Musya8 [376]

ANSWER

The greatest common factor is
${x}^{2} y$

EXPLANATION

We want to find the greatest common factor of

$9 {x}^{2} y$

and

$5 {x}^{4} {y}^{2}$

The prime factorizations are;

$9 {x}^{2} y = {3}^{2} \times {x}^{2} \times y$

and

$5 {x}^{4} {y}^{2} = 5 \times {x}^{4} \times {y}^{2}$

The product of the least powers of the common factors is the greatest common factor.

$= {x}^{2} y$

7 0

3 years ago

Find the mistake in the problem. tell what is is.<br>6th grade math

nirvana33 [79]

He / she didn’t drop down the 2 after subtracting 19 from 242, instead he / she dropped down a 0.

7 0

3 years ago

A car is towed using a force of 1600N. The rope used to pull the car makes an angle of 25∘ with the horizontal. Find the work do

mezya [45]

Answer: 2900185 Joules

Step-by-step explanation:

Force used to tow the car is 1600N

Angle(α)= 25

Displacement = 2km

Recall that 1km= 1000m

Therefore 2km= 2000m

Workdone= FdCos α

W= 1600 * 2000 * cos 25

W=2900184.919

W= 2900185 Nm(when approximated to the nearest integer)

Since 1J = 1Nm

Work done = 2900185 J

5 0

3 years ago

What is 9 1/2 - 5 7/12 =

Soloha48 [4]

Answer:

47/12, or 3 11/12

Step-by-step explanation:

9 1/2 - 5 7/12 > convert to improper fractions

19/2 - 67/12

make same denominator (12)

19/2 * 6 = 114/12

114/12 - 67/12 = 47/12

7 0

2 years ago

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