Answer:
by dividing and subtracting
Step-by-step explanation:
Larger PyramidHeight 24 Volume 648
Pyramid Volume = (Area of the Base * Height) ÷ 3648 = Base Area * 24 / 3Base Area = 648 * 3 / 24Base Area = 648 / 8Base Area = 81Base Length = 9
a) The Scale Factor between the Small & Large PyramidLength - 3LATERAL Area - 9Volume - 27
Slant Height^2 = 4.5^2 + 24^2Slant Height^2 =
<span>
<span>
596.25
</span>
</span>
<span><span>Slant Height^2 = 24.4182308941
</span>
</span>
b)
Large Pyramid Area = (½ * Perimeter of Base * Slant Height) + Base AreaLarge Pyramid Area = (.5 * 36 * <span>24.4182308941) + 81
</span>Large Pyramid Area = 439.5281560938 + 81
Large Pyramid TOTAL Area =
<span>
<span>
520.5281560938
</span>
</span>
<span>Large Pyramid LATERAL Area =<span> 439.5281560938
</span>
</span>
**********************************************************************************c)
Smaller PyramidHeight 8Surface Area = 124
This pyramid has dimensions that are one third of the larger pyramid.Therefore, it has a base length of 3.Base Area = 9.
Its base perimeter would be 12.
Small Pyramid Volume = (Area of the Base * Height) ÷ 3Small Pyramid Volume = ( 9 * 8 ) / 3Small Pyramid Volume = 72 / 3
c) Small Pyramid Volume =24 cubic meters
d) Ratio of larger pyramid volume to smaller pyramid volume648 / 24 = 27The reason? Volume is a 3 dimensional quantity. The Larger pyramid is 3 times larger in terms of the base measurement.9 meters vs 3 meters - a factor of 3When we compare volumes, we have to cube this factor.3^3 = 27
Source : http://www.1728.org/volpyrmd.htm
A plumber worked 26 hours a week for half a year. If his hourly wage was $40, how much did he earn during this time period?
<span> <span>A.</span>$1040</span><span> <span>B.</span>$27,040</span><span> <span>C.</span>$54,080</span><span> <span>D.</span><span>$520</span></span>
Answer:
x=42°
Step-by-step explanation:
We know that 2 of the legs are congruent, so the angles opposite them will be congruent.
The angles of a triangle add up to 180°
This can be represented by 


<u>Hope this helps :-)</u>