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Elden [556K]
3 years ago
5

What is 2(n+5)=-2 showing work

Mathematics
2 answers:
olganol [36]3 years ago
8 0
Simplify:
2n+10=-2

Subtract 10 from both sides
2n+10-10=-2-10
2n=-12

Divide both sides by 2
2n/2=-12/2

n=-6
BabaBlast [244]3 years ago
4 0
2(n + 5) = -2

First, our goal to this problem is to get the variable (n) and an unknown number on each side. To start off, we can divide both sides by 2.
n + 5 =  -\frac{2}{2}

Second, we can go ahead and cancel 2 out, which will replace it with a -1.
n + 1 = -1

Third, our next step will to be to subtract 5 from each side.
n = -1 - 5

Fourth, our last step is to simplify -1 - 5. This is quite simple. -1 - 5 = -6, so -6 is what the variable (n) equals. 
n = -6

Answer: \fbox {n = -6}
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Answer:

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Step-by-step explanation:

5 0
3 years ago
Determine what type of model best fits the given situation:
lyudmila [28]

Let value intially be = P

Then it is decreased by 20 %.

So 20% of P = \frac{20}{100} \times P = 0.2P

So after 1 year value is decreased by 0.2P

so value after 1 year will be = P - 0.2P (as its decreased so we will subtract 0.2P from original value P) = 0.8P-------------------------------------(1)

Similarly for 2nd year, this value 0.8P will again be decreased by 20 %

so 20% of 0.8P = \frac{20}{100} \times 0.8P = (0.2)(0.8P)

So after 2 years value is decreased by (0.2)(0.8P)

so value after 2 years will be = 0.8P - 0.2(0.8P)

taking 0.8P common out we get 0.8P(1-0.2)

= 0.8P(0.8)

=P(0.8)^{2}-------------------------(2)

Similarly after 3 years, this value P(0.8)^{2} will again be decreased by 20 %

so 20% of P(0.8)^{2}  \frac{20}{100} \times P(0.8)^{2} = (0.2)P(0.8)^{2}

So after 3 years value is decreased by (0.2)P(0.8)^{2}

so value after 3 years will be = P(0.8)^{2}   - (0.2)P(0.8)^{2}

taking P(0.8)^{2} common out we get P(0.8)^{2}(1-0.2)

P(0.8)^{2}(0.8)

P(0.8)^{3}-----------------------(3)

so from (1), (2), (3) we can see the following pattern

value after 1 year is P(0.8) or P(0.8)^{1}

value after 2 years is P(0.8)^{2}

value after 3 years is P(0.8)^{3}

so value after x years will be P(0.8)^{x} ( whatever is the year, that is raised to power on 0.8)

So function is best described by exponential model

y = P(0.8)^{x} where y is the value after x years

so thats the final answer

3 0
3 years ago
Mandy is selling pancakes and waffles at her diner. On Monday she sold a total of 300 pancakes and waffles. If she charges $3 pe
elena-s [515]

Answer:

Mandy sold 250 pancakes and 50 waffles.

Step-by-step explanation:

From the information given, you can say that the sum of pancakes and waffles is equal to 300:

x+y=300

Also, the statement indicates that she charges $3 per pancake, $1 per waffle, and made a total of $800 and you can express this as:

3x+y=800

You have the following equations:

x+y=300 (1)

3x+y=800 (2), where:

x is the number of pancakes she sold

y is the number of waffles she sold

Now, you can solve for x in (1):

x=300-y (3)

Then, you can replace (3) in (2):

3(300-y)+y=800

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y=100/2

y=50

Finally, you can replace the value of y in (3) to find x:

x=300-50

x=250

According to this, the answer is that Mandy sold 250 pancakes and 50 waffles.

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