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3 years ago

11

a rectangular playground has a preimeter of 180 feet.if the length is 12 feet longer than the width, what are the dimensions of

the playground?

1 answer:

jeka943 years ago

4 0

Perimeter = w + w + l + l
180= w+w+w+12+w+12
The dimensions for width are just w and for length it's w+12

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castortr0y [4]

Answer:

C. 3x + 30

Step-by-step explanation:

Distribute:

=(5)(2x) + (5)(6) + −7x

=10x + 30 + −7x

Combine Like Terms:

=10x + 30 + −7x

=(10x + −7x) + (30)

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3 0

3 years ago

Read 2 more answers

What does 4(m-2)=2(m-9) equal

marshall27 [118]

Answer:

m = -5

Step-by-step explanation:

Simplify both sides of the equation.

4(m−2)=2(m−9)

(4)(m)+(4)(−2)=(2)(m)+(2)(−9)(Distribute)

4m+−8=2m+−18

4m−8=2m−18

Subtract 2m from both sides.

4m−8−2m=2m−18−2m

2m−8=−18

Add 8 to both sides.

2m−8+8=−18+8

2m=−10

Divide both sides by 2.

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3 0

3 years ago

What is lim x→3 x^2 - x - 6/ x - 3

Kisachek [45]

<h3>Answer: D) 5</h3>

=======================================================

Explanation:

If we plugged x = 3 into the expression, then we'd get x-3 = 3-3 = 0 in the denominator. That's not allowed. But we can simplify first

x^2-x-6 factors to (x-3)(x+2). The key here is that (x-3) is a factor. It cancels with the x-3 in the denominator

So, $\frac{x^2-x-6}{x-3} = \frac{(x-3)(x+2)}{x-3} = x+2$

Allowing us to say,

$\displaystyle \lim_{x \to 3}\frac{x^2-x-6}{x-3} = \lim_{x \to 3}\frac{(x-3)(x+2)}{x-3}\\\\\\\displaystyle \lim_{x \to 3}\frac{x^2-x-6}{x-3} = \lim_{x \to 3}(x+2)\\\\\\\displaystyle \lim_{x \to 3}\frac{x^2-x-6}{x-3} = 3+2\\\\\\\displaystyle \lim_{x \to 3}\frac{x^2-x-6}{x-3} = 5\\\\\\$

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3 years ago

Solve the following word problems using a system of equations. The sum of two numbers is 36. One number is two more than the oth

juin [17]

Answer:

24,12

Step-by-step explanation:

suppose,

x+y=36

x=2y

2y+y=36

y=12

x=24

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3 years ago

City R has a temperature of -2 degrees. City S has a temperature of -6 degrees. Write an inequality to compare the temperatures

elena-s [515]

Answer:

-2 > -6 . . . or . . . R > S

Step-by-step explanation:

If you plot the temperatures of the two cities on a number line, you see that the temperature for City R is plotted to the right of the temperature for City S. This means the temperature of City S is less than that of City R.

If your inequality relates cities:

S < R or R > S

If your inequality relates temperatures:

-6 < -2 or -2 > -6

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3 years ago