Find 2x2 − 2z4 + y2 − x2 + z4 if x = −4, y = 3, and z = 2.

1 answer:

3 0

If you put in the substitutions it would be 2*2-(2*2*4)+(3*2)-(-4*2)+(2*4).
Simplified further by multiplying it would be 2*2-8+6--8+8
the negative 8 could be simplified further since the negatives cancel out so you'll have 2*2-8+6+8+8.
Then using the order of operations you would multiply the 2's together first to get 4 so you have 4-8+6+8+8.
After that it's simple addition giving you an answer of -26.
I'm not sure if you're looking for the final answer or just the equation with substitutions but there's both.

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Solve: (x ÷ 4) + 8 = 38

Rainbow [258]

First you have to rewrite the equation:
(x ÷ 4) + 8 = 38

Second you have to write the division as fraction:
(¼x) + 8 = 38

Third you have to take off the unecessary bracket:

¼x + 8 = 38

Fourth multiply 8 and 38 by 4
x + 32 = 152

Fifth step move the constant to the right hand and change the sign.
x = 152 - 32

Then subtract:

x = 120

Hope this helps :))

5 0

2 years ago

Where is the function f(x)=3x^2-6x-45/x^2-5x discontinuous, and what types of discontinuities does it have?

Vedmedyk [2.9K]

Answer:

Below.

Step-by-step explanation:

f(x)=3x^2-6x-45/x^2-5x

= 3x^2-6x-45 / (x(x - 5))

The denominator is zero when x - 0 and x = 5.

So there will be a vertical asymptote at x = 0 and a hole at x = 5.

If we do the division we get f(x) = 3 remainder 9x - 45