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3 years ago

How would you write and name the ions for tin?

1 answer:

3 0

For Single Element Ions (e.g. K+ , Mg2+, P3-) To name positive (+) ions write the name as from the Periodic Table and add the word 'ion' afterwards. To name negative (-) ions write the name from the Periodic Table but replace the ending with 'ide'. Put the word 'ion' after the name.

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7. How many moles are in 5 x 10 2 atoms of gold?

goblinko [34]

Answer:

8.3028894e-22

Explanation:

5x10^2 atoms/1 x 1 mol/6.022x10^23

7 0

2 years ago

Which equation represents a double replacement reaction?

AveGali [126]

Answer:

C) LiOH + HCl → LiCl + H₂O

General Formulas and Concepts:

Chemistry - Reactions

Synthesis Reactions: A + B → AB
Decomposition Reactions: AB → A + B
Single-Replacement Reactions: A + BC → AB + C
Double-Replacement Reactions: AB + CD → AD + BC

Explanation:

Step 1: Define

RxN A: 2Na + 2H₂O → 2NaOH + H₂

RxN B: CaCO₃ → CaO + CO₂

RxN C: LiOH + HCl → LiCl + H₂O

RxN D: CH₄ + 2O₂ → CO₂ + 2H₂O

Step 2: Identify

RxN A: Single Replacement Reaction

RxN B: Decomposition Reaction

RxN C: Double Replacement Reaction

RxN D: Combustion Reaction

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2 years ago

Post good memes for brainlyest

Katen [24]

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Explanation:

7 0

2 years ago

Read 2 more answers

A 44% wt/wt solution of H2SO4 has a density of 1.343g/ml. What mass of H2SO4 is 60ml of this solution?

horsena [70]

Answer: The mass of sulfuric acid present in 60 mL of solution is 34.1 grams

Explanation:

We are given:

44 % (m/m) solution of sulfuric acid. This means that 44 grams of sulfuric acid is present in 100 grams of solution.

To calculate volume of a substance, we use the equation:

$\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}$

Density of solution = 1.343 g/mL

Mass of solution = 100 g

Putting values in above equation, we get:

$1.343g/mL=\frac{100g}{\text{Volume of solution}}\\\\\text{Volume of solution}=\frac{100g}{1.343g/mL}=77.46mL$

To calculate the mass of sulfuric acid present in 60 mL of solution, we use unitary method:

In 77.46 mL of solution, mass of sulfuric acid present is 44 g

So, in 60 mL of solution, mass of sulfuric acid present will be = $\frac{44g}{77.46mL}\times 60mL=34.1g$

Hence, the mass of sulfuric acid present in 60 mL of solution is 34.1 grams

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2 years ago

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Lyrx [107]

Answer:

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2 years ago