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Reptile [31]
3 years ago
14

Marina walks from the police station at (-10, -4) to her friend Marissa’s house at (3, -8). She stops half way at a fast food re

staurant to buy a soda. What are the coordinates where she stops?
Mathematics
1 answer:
Volgvan3 years ago
8 0
\bf \textit{middle point of 2 points }\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
%  (a,b)
&({{ -10}}\quad ,&{{ -4}})\quad 
%  (c,d)
&({{ 3}}\quad ,&{{ -8}})
\end{array}\qquad
%   coordinates of midpoint 
\left(\cfrac{{{ x_2}} + {{ x_1}}}{2}\quad ,\quad \cfrac{{{ y_2}} + {{ y_1}}}{2} \right)
\\\\\\
\left( \cfrac{3-10}{2}~~,~~\cfrac{-8-4}{2} \right)
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The answer is D. "x=-15 or 15."

You can solve this by adding seven on both sides.
|x|-7=8
   +7 +7
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|x|=15

Therefore, x is either equal to 15 or -15.
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A man drive 250 miles on 2.5 hours.if the posted speed limit was 75 mph the entire way, approximately how many miles per hour ov
kow [346]

Answer:

He was going 25 miles over the speed limit.

Step-by-step explanation:

250 miles in 2.5 hours is 250/2.5. That equals 100

100-75=25

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Pls solve: 4x+7-2x=4
miss Akunina [59]
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What is 2+2 then take away 1
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3

Step-by-step explanation:

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4 0
3 years ago
Read 2 more answers
Write an equation of the circle that has a diameter with endpoints (12, 3) and<br> (-18,3).
Mademuasel [1]

The equation of the circle that has a diameter with endpoints (12, 3) and(-18,3) is x² + y² + 6x - 6y - 207 = 0

<h3>Coordinates of center of circle</h3>

Since the endpoints of the diameter are (x₁, y₁) = (12,3) and (x₂, y₂) = (-18,3), the coordinates of the center of the circle are the midpoints of the diameter. So, the midpoints are

  • x = (x₁ + x₂)/2 = (12 + (-18))/2 = (12 - 18)/2 = -6/2 = -3 and
  • y = (y₁ + y₂)/2 = (3 + 3)/2 = 6/2 = 3.

So, the coordinates of the center of the circle are (-3, 3)

<h3>The radius of the circle</h3>

The radius of the circle r = √[(x₁ - h)² + (y₁ - k)²] where

  • (x₁, y₁) = coordinates of end of diameter = (12, 3) and
  • (h, k) = coordinates of center of circle = (-3, 3)

So, substituting the values of the variables into r, we have

r = √[(x₁ - h)² + (y₁ - k)²]

r = √[(12 - (-3))² + (3 - 3)²]

r = √[(12 + 3)² + 0²]

r = √[15² + 0²]

r = √15²

r = 15

<h3>The equation of the circle</h3>

The equation of a circle with center (h,k) is given by

(x - h)² + (y - k)² = r² where r = radius of circle.

Substituting the values of the variables into the equation, we have

(x - h)² + (y - k)² = r²

(x - (-3))² + (y - 3)² = 15²

(x + 3)² + (y - 3)² = 15²

x² + 6x + 9 + y² - 6y + 9 = 225

x² + 6x + y² - 6y + 9 + 9 - 225 = 0

x² + y² + 6x - 6y - 207 = 0

The equation of the circle that has a diameter with endpoints (12, 3) and(-18,3) is x² + y² + 6x - 6y - 207 = 0

Learn more about equation of a circle here:

brainly.com/question/18435467

5 0
2 years ago
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