All categories

3 years ago

Line RS bisects PQ at point R. Find RQ if PQ = 4 3/4

2 answers:

8 0

PQ is bisected by RS at R. It means that PRQ is a line segment with PR = RQ and each of half of PQ.

RQ = PQ/2 = 1/2 [ 4 3/4 ] = 1/2 * 19/4 = 19/8  = 2 3/4

Citrus2011 [14]3 years ago

3 0

$|PQ|=2\cdot| RQ|\ \ \ \Rightarrow\ \ \ 4 \frac{3}{4} =2\cdot |RQ|\ /:2\ \ \ \Rightarrow\ \ \ \frac{19}{4}\cdot \frac{1}{2} = |RQ|\\\\|RQ|=\frac{19}{8}=2 \frac{3}{8}$

You might be interested in

You are driving due north on the highway. Ahead, but off to the East, you see a tall tower. Sketch a graph or make a table showi

valentina_108 [34]

Answer:

The amount of speed you go will determine the graph but it should go closer and closer but then farther away because you drive past the tower

Step-by-step explanation:

3 0

4 years ago

Yesny had $240 to spend on five pairs of jeans. How much did each pair of

krek1111 [17]

Answer:

5x + 10 = 240

Step-by-step explanation:

3 0

4 years ago

Read 2 more answers

Persons having Raynaud's syndrome are apt to suffer a sudden impairment of blood circulation in fingers and toes. In an experime

Citrus2011 [14]

Answer:

There is enough evidence to say that the true average heat output of persons with the syndrmoe differs from the true average heat output of non-sufferers.

Step-by-step explanation:

We have to perform a hypothesis test on the difference between means.

The null and alternative hypothesis are:

$H_0: \mu_1-\mu_2=0\\\\H_a: \mu_1-\mu_2$

μ1: mean heat output for subjects with the syndrome.

μ2: mean heat output for non-sufferers.

We will use a significance level of 0.05.

The difference between sample means is:

$M_d=\bar x_1-\bar x_2=0.63-2.09=-1.46$

The standard error is

$s_{M_d}=\sqrt{\sigma_1^2/n_1+\sigma_2^2/n_2}=\sqrt{0.3^2/9+0.5^2/9}=\sqrt{ 0.038 } \\\\ s_{M_d}=0.194$

The t-statistic is

$t=\dfrac{M_d}{s_{M_d}}=\dfrac{-1.46}{0.194}=-7.52$

The degrees of freedom are

$df=n_1+n_2-2=9+9-2=16$

The critical value for a left tailed test at a significance level of 0.05 and 16 degrees of freedom is t=-1.746.

The t-statistic is below the critical value, so it lies in the rejection region.

The null hypothesis is rejected.

There is enough evidence to say that the true average heat output of persons with the syndrmoe differs from the true average heat output of non-sufferers.

5 0

3 years ago

Surveys indicate that two-thirds of all voters in Ward 5 plan on choosing Spike Jones for commissioner. If there are 500 voters

olya-2409 [2.1K]

Answer:

333 people of ward 5 are going to be voting for Spike Jones.

Solution:

We have been given that two-thirds of all voters in Ward 5 plan on choosing Spike Jones for commissioner.

There are 500 voters in Ward 5.

Since 2/3 of all voters in Ward 5 are voting for Spike Jones the remaining 1/3 will not be voting for him.

To find out how many people in ward 5 are exactly voting for Spike Jones. We need to calculate how much is two thirds of 500 is.

This is done as follows:

$\begin{array}{l}{\frac{2}{3} \times 500} \\\\ {=\frac{1000}{3}} \\\\ {=333.334}\end{array}$

Since people cannot be denoted in decimal points we have to round it off to a whole number. That’s is 333.

Therefore 333 people of ward 5 are going to be voting for Spike Jones.

4 0

3 years ago

Find the area of the composite figure in terms of pie 3cm Length and 5 cm in width

cluponka [151]

The area will be 15

5 0

3 years ago