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morpeh [17]
3 years ago
15

Can anyone help me with the 7th and 8th question which I have taken a bad photo of?

Mathematics
1 answer:
Vsevolod [243]3 years ago
7 0
<u>Question 7:

Define x :
</u>
Let the digit in the ones place be x.
The digit in the tens place is  x+2.

The sum of the digit and its reverse is 66

<u>Find x:</u>

10(x + 2) + x + 10x + (x + 2) = 66
10x  + 20 + x + 10x + x + 2 = 66
22x + 22 = 66
22x = 44
x = 2

<u>Find the number:</u>

The number in the ones place = x= 2
The number in the tens place = x = 2 + 2 = 4

Answer : The number is 42.

<u>Question 8:</u>

<u>Define x:</u>

Let the digit in the tens place be x.
The digit in the ones place is x+7.

The number  = 10x + x + 7 = 11x + 7

If the digit interchange,
the number = 10(x + 7) + x = 10x + 70 + x = 11x + 70

<u>Find x:
</u>
9(11x + 7) = 2(11x + 70)
99x + 63 = 22x + 140
99x - 22x = 140 - 63
77x = 77
x = 1

<u>Find the number:
</u>
x = 1
x + 7 = 1 + 7 = 8
So the number is 18

Answer: The number is 18.

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4 years ago
A particle travels along a straight line with a velocity of v(t)=3e^(-1/2)sin(2t) meters per second. What is the total distance
KatRina [158]
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<span>. . . . . . . . . . . . . = −6/17 (e^(−π/4) (0 − 4) − (0 + 4)) </span>
<span>. . . . . . . . . . . . . = −6/17 (−4e^(−π/4) − 4) </span>
<span>. . . . . . . . . . . . . = 24/17 (e^(−π/4) + 1) </span>
<span>. . . . . . . . . . . . . = 2.05544 
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∫[π/2 to 2] v(t) dt = ∫[π/2 to 2] (3 e^(−t/2) sin(2t)) dt 
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7 * 2 = 14

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3. we must round 4/9

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8/18 for that to be 1/2 it would need 1/18. Thus this rounds up to 1/2.

4. We must round 3 5/7

5/7 would round up to a whole number.

3 + 1 = 4

Thus 3 5/7 = 4 when rounded to the nearest whole number.

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