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3 years ago

15

Can anyone help me with the 7th and 8th question which I have taken a bad photo of?

1 answer:

Vsevolod [243]3 years ago

7 0

<u>Question 7:

Define x :
</u>
Let the digit in the ones place be x.
The digit in the tens place is x+2.

The sum of the digit and its reverse is 66

<u>Find x:</u>

10(x + 2) + x + 10x + (x + 2) = 66
10x + 20 + x + 10x + x + 2 = 66
22x + 22 = 66
22x = 44
x = 2

<u>Find the number:</u>

The number in the ones place = x= 2
The number in the tens place = x = 2 + 2 = 4

Answer : The number is 42.

<u>Question 8:</u>

<u>Define x:</u>

Let the digit in the tens place be x.
The digit in the ones place is x+7.

The number = 10x + x + 7 = 11x + 7

If the digit interchange,
the number = 10(x + 7) + x = 10x + 70 + x = 11x + 70

<u>Find x:
</u>
9(11x + 7) = 2(11x + 70)
99x + 63 = 22x + 140
99x - 22x = 140 - 63
77x = 77
x = 1

<u>Find the number:
</u>
x = 1
x + 7 = 1 + 7 = 8
So the number is 18

Answer: The number is 18.

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4 ( − )−62−32( 22− )+2( − )<br><br> please help

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Answer:

-772

Step-by-step explanation:

First, multiply the brackets with the numbers before them:

4(-) = -4

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Then put them back into the question

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Subtract them to get the answer

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<em>PS: Not sure if it completely correct but it’s worth a try.</em>

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Step-by-step explanation:

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3 years ago

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scZoUnD [109]

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3 years ago

Help me. The graph of a polynomial with unknown a is given. Write a polynomial

Xelga [282]

Answer:

$f(x)=\dfrac{7}{20}\left(x+2\right)^{2}\left(x-1\right)$ .

Step-by-step explanation:

If a graph touches the x-axis at x=c, then (x-c) is a factor of function.

From the given graph it is clear that the graph of function intersect x-axis at x=1 and touch the x-axis at x=-2.

It means (x-1) and (x+2) are not factors of given function but power of (x+2) must be 2.

So, the required function is

$f(x)=a(x+2)^2(x-1)$ ...(1)

where, a is a constant.

From the given figure it is clear that the graph passes through the point (-4,-7). So, substitute x=-4 and f(x)=-7 in the above function.

$-7=a(-4+2)^2(-4-1)$

$-7=a(-2)^2(-5)$

$-7=-20a$

$\dfrac{7}{20}=a$

Substitute $a=\dfrac{7}{20}$ in (1).

$f(x)=\dfrac{7}{20}(x+2)^2(x-1)$

Therefore, the required function is $f(x)=\dfrac{7}{20}(x+2)^2(x-1)$ .

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3 years ago