Can anyone help me with the 7th and 8th question which I have taken a bad photo of?

Mathematics

1 answer:

Vsevolod [243]3 years ago

7 0

Question 7:

Define x :

Let the digit in the ones place be x.
The digit in the tens place is x+2.

The sum of the digit and its reverse is 66

Find x:

10(x + 2) + x + 10x + (x + 2) = 66
10x + 20 + x + 10x + x + 2 = 66
22x + 22 = 66
22x = 44
x = 2

Find the number:

The number in the ones place = x= 2
The number in the tens place = x = 2 + 2 = 4

Answer : The number is 42.

Question 8:

Define x:

Let the digit in the tens place be x.
The digit in the ones place is x+7.

The number = 10x + x + 7 = 11x + 7

If the digit interchange,
the number = 10(x + 7) + x = 10x + 70 + x = 11x + 70

Find x:

9(11x + 7) = 2(11x + 70)
99x + 63 = 22x + 140
99x - 22x = 140 - 63
77x = 77
x = 1

Find the number:

x = 1
x + 7 = 1 + 7 = 8
So the number is 18

Answer: The number is 18.

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Take the integral:

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$\large\textsf{I hope it helps. :-)}$


Tags: integrate indefinite integral substitution exponential base logarithm log ln composite integral calculus

4 0

3 years ago

52 + 3x = 5(−x + 9) − 49 solve for x

Tems11 [23]

Answer:

x = -7

Step-by-step explanation:

52 + 3x = -5x + 45 - 49

8x = -56

x = -7

3 0

2 years ago