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melomori [17]
4 years ago
14

50 POINTS!! PLEASE HELP!

Chemistry
1 answer:
inn [45]4 years ago
8 0
Okay so the answer will be.
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Isn’t Bambi undo hall
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Why would an atom emit particles or waves from its nucleus?
Neko [114]

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It’s A non of these

Explanation:

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The breakdown of dopamine is catalyzed by the enzyme monoamine oxidase (MAO). What is the final concentration of product if the
kotegsom [21]

Answer:

final concentration: Ca = 0.014 M

Explanation:

Velocity of reaction:

  • ra = K(Ca)∧α = δCa/δt

∴ α: order of reaction, assuming α = 1

∴ K = 0.249 s-1.......rate constant

∴ Cao = 0.050 M......initial concentration

∴ t = 5 s.......reaction time

⇒ δCa/δt = K*Ca

⇒ ∫δCa/Ca = K*∫δt

⇒ Ln(Cao/Ca) = K*t = (0.249s-1)(5 s) = 1.245

⇒ Cao/Ca = 3.473

⇒ Ca = 0.050/3.473

⇒ Ca = 0.014 M

3 0
3 years ago
Read 2 more answers
Decide which of the following statements are True and which are False about equilibrium systems:A large value of K means the equ
ivanzaharov [21]

Answer:

a. True

b. False

c. True

d.  False

e. False

Explanation:

A. (true) The equilibrium constant K is defined as

\frac{Products}{reagents}

In any case  

aA +Bb ⇌ Cd +dD

where K is:

K= \frac{[C]^{c}[D]^{d}}{[A]^{a}[B]^{b}}

A large value on K means that the concentration of products is bigger than the concentrations of reagents, so the forward reaction is favored, and the equilibrium lies to the right.

B. (False) When we work with gases, we use partial pressure to make calculations in the equilibrium, so we estimate Kp as:

Kp= \frac{(P_{C})^{c}(P_{D})^{d}}{(P_{A})^{a}(P_{B})^{b}}

Using the ideal gas law, we can get a relationship between K and Kp  

Pv=nRT where P=\frac{n}{v}*RT we know that \frac{n}{v} is the molar concentration. When we replace P in the expression for Kp we get:

Kp= \frac{[C]^{c}*(RT)^{c}[D]^{d}*(RT)^{d}}{[A]^{a}*(RT)^{a}[B]^{b}*(RT)^{b}}

Reorganizing the equation:

Kp= \frac{[C]^{c}[D]^{d}}{[A]^{a}[B]^{b}}*\frac{(RT)^{c+d}}{(RT)^{a+b}}

We can see K in the expression  

Kp= K*(RT)^{c+d-a-b}

Delta n = c+d-a-b

Kp= K*(RT)^{delta n}

For the reaction  

H_{2}(g) + F_{2}(g)-- equilibrium---2HF(g)

Delta n = 2-1-1=0

Kp= K*(RT)^{0}

So Kp=K in this case.

C. (true) The value of K just depends on the temperature that’s why changing the among of products won’t have any effect on its value.  

D. (false) as we can see this reaction involve a heterogeneous system with solids and gases. For convention the concentration for solids and liquids can be considered constant during the reaction that’s why they’re not include in the calculation for the equilibrium constant. Taking this into account the expression for the equilibrium for this reaction is:

CaCO_{3}(s)---equilibrium----CaO(s) + CO_{2}(g)

K= [CO_{2}]

So we can see that [CaCO_{3}] is not include in the expression.  

E. (False) The equilibrium is defined as the point where the rate of the forward reaction is the same to the rate of the reverse reaction. The value of K is telling you which reaction is favored but the rate of both reactions is the same in this point. (see picture)  

3 0
3 years ago
¿En qué ecosistema de Puerto Rico abunda más el pez Mero?
Sphinxa [80]

Answer:

Mostly abundant Coral reef ecosystem

Explanation:

We know that,

There are 7 ecosystem in puerto rico but the grouper fisher such as nassau grouper is one of them that present in coral reef ecosystem.

Nassau grouper fish is one of the grouper fish that present in puerto rico island. It is now announced as danger in the US, and as risk by the International Union for Conservation of Nature.

Hence, Coral reef ecosystem is the most abundant in Puerto Rico

3 0
4 years ago
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