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The percentage of Chromium in Chromium Oxide is calculated as follow,
Step 1:
Calculate Molar mass of Cr₂O₃,
Cr = 51.99 u
O = 16 u
So,
2(51.99) + 3(16) = 103.98 + 48 = 151.98 u
Step 2:
Secondly divide molar mass of only chromium with total mass of Cr₂O₃ and multiply with 100.
i.e.
=
× 100
= 68.41 %
So, the %age composition of chromium in chromium oxide is 68.41 %.
Step 1:
Calculate Molar mass of Cr₂O₃,
Cr = 51.99 u
O = 16 u
So,
2(51.99) + 3(16) = 103.98 + 48 = 151.98 u
Step 2:
Secondly divide molar mass of only chromium with total mass of Cr₂O₃ and multiply with 100.
i.e.
=
= 68.41 %
So, the %age composition of chromium in chromium oxide is 68.41 %.
Explanation: This is a reaction of oxidation of in the presence of acidified
. Acidified
is a strong oxidizing agent.
To balance out the on the reactant side, we write
on the product side.
Balancing out the following reaction gives us: