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Lady_Fox [76]
3 years ago
10

Relative dating methods help scientists to _____.

Chemistry
2 answers:
klasskru [66]3 years ago
8 0
<span>identify the order in which rock units formed</span>
gogolik [260]3 years ago
6 0

identify the order in which they formed


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What happens when the calcium burns in the oxygen. write the chemical reaction​
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Calcium can be ignited and will when burning react with both oxygen and nitrogen forming calcium oxide, CaO, and calcium nitride, Ca3N2.

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Glucose and oxygen are the reactants in
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How cations can become neutral atoms?​
Vedmedyk [2.9K]
A neutral atom contains the same number of electrons as protons and that means that the electric charge of the atom is neutral or otherwise known as zero. However, if a particular atom loses an electron, the atom becomes positively charged because there is more protons than electrons.
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hope this helps x
3 0
3 years ago
Read 2 more answers
What is the negatively charged subatomic particle located outside the nucleus of an atom
Mars2501 [29]
The answer is electron
8 0
3 years ago
A mixture of 1.374g of H2 and 70.31g of Br2 is heated in a 2.00 L vessel at 700 K. These substances react as follows: H2(g) + Br
gregori [183]

Answer:

a. 0.139 M → [H₂] ; 0.217 M → [Br₂] ; 0.01 M → [HBr]

b. Kc =  3.31x10⁻³

Explanation:

                  H2(g)   +   Br2(g)     ⇄  2HBr(g)

Initial        1.374 g       70.31 g             -

reacts            X                X                2x

eq.           (1.374 - x)     (70.31-x)         2x

<em>In equilibrium I see, the grams I initially had minus some mass which has reacted. In products I have the double of that mass, because the stoichiometry.</em>

So I have the mass in equilibrium, of H2 and of course I can know the mass which has reacted.

1.374g - x = 0.556 g

1.374g - 0.556 g = x = 0.808 g (This is the mass which has reacted)

70.31g  - 0.808 g = 69.502 g (Mass in equilibrium of Br2)

2 . 0.808 g = 1.616 g (Mass in equibrium of HBr)

By molar mass, we can kwow the moles.

Molar mass H2: 2 g/m  

Moles = mass / molar mass  → 0.556 g / 2 g/m = 0.278 moles

Molar mass Br2: 159.80 g/m

Moles = mass / molar mass  → 69.502 g / 159.80 g/m = 0.434 moles

Molar mass HBr: 80.9 g/m

Moles = mass / molar mass → 1.616 g / 80.9 g/m = 0.02 moles

The moles are not molarity. In equilibrium, to calculate Kc we need molarity (moles/L). The moles we have calculated are in 2 L of mixture so:

moles / L = molarity

0.278 moles / 2L = 0.139 M → [H₂]

0.434 moles / 2L = 0.217 M → [Br₂]

0.02 moles / 2L = 0.01 M → [HBr]

Kc =  [HBr]² / ([H₂] . [Br₂])

Kc = 0.01² / (0.139 . 0.217) = 3.31x10⁻³

6 0
3 years ago
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