Answer:
Glucose would not be able to get into the cell treated with this chemical
Potassium mwill not be able to move or transport may be affected
Explanation:
As all membrane transport proteins are inactivated glucose is abig molecule it cannot pass without transporter protein.
Potassium transport is through sodium potassium pump and leak channels. As all transport protein are affected so it should not be able to move but if drug does not affect them then they will be unaffected.
Explanation:
The balanced equation of the reaction is given as;
Mg(OH)2 (s) + 2 HBr (aq) → MgBr2 (aq) + 2 H2O (l)
1. How many grams of MgBr2 will be produced from 18.3 grams of HBr?
From the reaction;
2 mol of HBr produces 1 mol of MgBr2
Converting to masses using;
Mass = Number of moles * Molar mass
Molar mass of HBr = 80.91 g/mol
Molar mass of MgBr2 = 184.113 g/mol
This means;
(2 * 80.91 = 161.82g) of HBr produces (1 * 184.113 = 184.113g) MgBr2
18.3g would produce x
161.82 = 184.113
18.3 = x
x = (184.113 * 18.3 ) / 161.82 = 20.8 g
2. How many moles of H2O will be produced from 18.3 grams of HBr?
Converting the mass to mol;
Number of moles = Mass / Molar mass = 18.3 / 80.91 = 0.226 mol
From the reaction;
2 mol of HBr produces 2 mol of H2O
0.226 mol would produce x
2 =2
0.226 = x
x = 0.226 * 2 / 2 = 0.226 mol
3. How many grams of Mg(OH)2 are needed to completely react with 18.3 grams of HBr?
From the reaction;
2 mol of HBr reacts with 1 mol of Mg(OH)2
18.3g of HBr = 0.226 mol
2 = 1
0.226 = x
x = 0.226 * 1 /2
x = 0.113 mol
The appropriate response is high. The best approach to consider it is those molecules have more vitality than the normal and it is unequivocally those higher enthusiastic ones that have enough vitality to break the intra-molecular forces and leave. By the way this is the reason when we sweat we chill off - the most enthusiastic molecules vanish diverting warmth.
Answer:
The calculations are in the explanation below.
The <em>steps </em>are:
- 1. Using a graduated pipette, accurately take 25mL of the 12.0M stock solution.
- 2. Pour the 25mL of stock solution into a 100 mL volumetric flask
- 3. Add distilled water up to the mark
- 4. Cap the flask with the stopper
- 5. Stirr by gently rotating the flask.
Explanation:
To make 100 mililiter of the 3.0M solution of sulfuric acid, first you must calculate the volume of the 12.0M stock solution that contains the same number of moles as the diluted solution.
For that, you use the dilution formula:
- number of moles = C₁V₁ = C₂V2
- V₁ = 3.0M × 100mL/12.0M = 25mL
Then, the steps are:
1. Using a graduated pipette, accurately take 25mL of the 12.0M stock solution.
2. Pour the 25mL of stock solution into a 100 mL volumetric flask
3. Add distilled water up to the mark
4. Cap the flask with the stopper
5. Stirr by gently rotating the flask.
