Answer:
The quantity of ascorbic acid found in sweet lime of 49.6 mg does not meet the daily requirement.
Explanation:
To determine the mass of ascorbic acid knowing the number of moles we use the following formula:
number of moles = mass / molecular weight
mass = number of moles × molecular weight
mass of ascorbic acid = 2.82 × 10⁻⁴ × 176
mass of ascorbic acid = 496 × 10⁻⁴ g = 0.0496 g = 49.6 mg
daily requirement of ascorbic acid = 70 - 90 mg
The quantity of ascorbic acid found in sweet lime of 49.6 mg does not meet the daily requirement.
Answer:
The answer to your question is V = 0.108 L or 108 ml
Explanation:
Data
Volume = ?
mass = 0.405 g
Temperature = 273°K
Pressure = 1 atm
Process
1.- Convert mass of Kr to moles
83.8 g of Kr -------------------- 1 mol
0.405 g ------------------- x
x = (0.405 x 1) / 83.8
x = 0.0048 moles
2.- Use the Ideal gas law to solve this problem
PV = nRT
- Solve for V
V = nRT / P
- Substitution
V = (0.0048)(0.082)(273) / 1
- Simplification
V = 0.108 / 1
- Result
V = 0.108 L
= 30802.53 im pretty sure if im wrong let me know its the best i can do :/
Answer:
156 g
Explanation:
Let's consider the following reaction.
2 NaN₃(s) → 2 Na(s) + 3 N₂
(g)
We can find the moles of N₂ using the ideal gas equation.
P × V = n × R × T
1.50 atm × 60.0 L = n × (0.08206 atm.L/mol.K) × 305 K
n = 3.60 mol
The molar ratio of N₂ to NaN₃ is 3:2. The moles of NaN₃ are:
3.60 mol N₂ × (2 mol NaN₃ / 3 mol N₂) = 2.40 mol NaN₃
The molar mass of NaN₃ is 65.01 g/mol. The mass of NaN₃ is:
2.40 mol × 65.01 g/mol = 156 g
CaCl2(aq) + K2CO3(aq) → 2 KCl(aq) + CaCO3(aq)
1.12 g
2.23 g
0.896 g
4.47 g
1.12 g
Hope it helps :)
