Drawing this square and then drawing in the four radii from the center of the cirble to each of the vertices of the square results in the construction of four triangular areas whose hypotenuse is 3 sqrt(2). Draw this to verify this statement. Note that the height of each such triangular area is (3 sqrt(2))/2.
So now we have the base and height of one of the triangular sections.
The area of a triangle is A = (1/2) (base) (height). Subst. the values discussed above, A = (1/2) (3 sqrt(2) ) (3/2) sqrt(2). Show that this boils down to A = 9/2.
You could also use the fact that the area of a square is (length of one side)^2, and then take (1/4) of this area to obtain the area of ONE triangular section. Doing the problem this way, we get (1/4) (3 sqrt(2) )^2. Thus,
A = (1/4) (9 * 2) = (9/2). Same answer as before.
18 = 2x + 4
2x = 14
x = 7
answer
first line: 1st box: 18 and 2nd box: 4
second line: $7 an hour
Answer:
Hey mate here's your answer.....
Step-by-step explanation:
Mathematics is a subject where you study more about numbers and daily life applications.
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Yes she does, shes also a great teacher for putting in the work for the production if the play.
You can't, the K cancels itself out. There is no solution to this
