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Nataliya [291]
3 years ago
15

What number between 1 and 100 have 12 factors​

Mathematics
1 answer:
kotykmax [81]3 years ago
7 0

Answer:

Your answer is:

60= 1, 2, 3, 4, 5, 6, 10, 12, 15, 20, 30, 60

72= 1, 2, 3, 4, 6, 8, 9, 12, 18, 24, 36, 72

84= 1, 2, 3, 4, 6, 7, 12, 14, 21, 28, 42, 84

90= 1, 2, 3, 5, 6, 9, 10, 15, 18, 30, 45, 90

96= 1, 2, 3, 4, 6, 8, 12, 16, 24, 32, 48, 96

The second-highest number of factors are 48 and 80, containing 10 factors each.

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Please help ! (FINALS)
anygoal [31]

Answer:

Rachel is correct

Step-by-step explanation:

We can calculate angle T by using cosine rule where;

t² = r² + m² - 2rm cos T

From the diagram, we see that;

t = 30

r = 18

m = 24

Thus;

30² = 18² + 24² - 2(18 × 24)cosT

900 = 324 + 576 - 864cosT

864cosT = 900 - 324 - 576

864cosT = 0

cosT = 0/864

T = cos^(-1) 0

T = 90°

8 0
3 years ago
Builders have observed that widows in a home are most attractive if they have the width to length ratio 3:5 if a window is to be
Helen [10]
The length should be 80 inches :

48÷3=16
16×5=80

3:5 = 48:80

Hope this helps : )
8 0
3 years ago
Please someone help me with this... and please thouroughly explain, i have no clue what to do.
Arlecino [84]

144. Use the formula for the volume of a cone, since the answer is in terms of pi disregard the pi in the formula and solve using (r^2)(h/3) which will give you the answer in terms of pi.

5 0
3 years ago
What is the algebraic expression to 6 less than twice a number
stellarik [79]

Answer:

it would be 2x-6

Step-by-step explanation:

since you don't know what the value of "the number" is you would put a variable, x. and there is 2 of this number.

then 6 less would be -6 of this variable.

7 0
3 years ago
How to solve for x in these shapes?
DiKsa [7]

Answer:

Step-by-step explanation:

a

sum of angles of a quadrilateral=360°

4x+5x+20+5x-10+3x+10=360

17x=360-20

17x=340

x=340/17

x=20

b.

sum of angles= (n-2)×180

where n is the number of sides.

5x+4x+2+5x+6+2x-2+3x+5+x-10=(6-2)×180

20x+1=720

20x=719

x=35.95

6 0
4 years ago
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