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Sidana [21]
3 years ago
14

A cone-shaped container has a height of 9 in. and diameter of 2 in. It is filled with a liquid that is worth $2 per cubic inch.

Mathematics
1 answer:
jeyben [28]3 years ago
3 0
If you would like to know the total value of the liquid in the container, you can calculate it using the following steps:

A cone:
a radius (r) ... 1 in.
a diameter ... 2 in.
a height (h) ... 9 in.
<span>π ... 3.14
</span>
Cone volume formula:
V = 1/3 * π * r^2 * h
V = 1/3 * 3.14 * 1^2 * 9 = 1/3 * 3.14 * 1 * 9
V = 9.42 cubic inches

$2 ... 1 cubic inch
$x = ? ... 9.42 cubic inches
_______________________
2 * 9.42 = 1 * x
x = 2 * 9.42
x = $18.84

The correct result would be $18.84.
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Triangle XYZ was dilated by a scale factor of 2 to create triangle ACB and sin ∠X = 5 over 5 and 59 hundredths.
Vikentia [17]

The relationship between Traingle XYZ and ACB is that they are similar triangles. tanX = tanA = 5 over 2 and 5 tenths, where

  • AC = 2 x  XY
  • CB = 2 x  YZ

<h3>What is the dilation about?</h3>

Triangle XYZ was dilated by a scale factor of 2 to create triangle ACB, hence XYZ and ACB are similar triangles.

Angles Y and C are said to measure 90 degrees, and angles A and X are known to be congruent. Thus:

tanX = tanA = 5 over 2 and 5 tenths

AC = 2 x  XY

CB = 2 x  YZ

Another way to solve for it is by:

Note that Dilation of the triangle ΔXYZ was by a factor of "2".

Since m∠Y = m∠C = 90º   - given

ΔXYZ and ΔACB are said to be right triangles.

Since ∠X ≅ ∠A   - given

Then ∠X and ∠Z are  said to becomplementary angles

Since m∠Z = 90° - m∠X   -- given

Then ∠A and ∠B are said to be complementary angles

Since m∠B = 90° - m∠A  --- given

Then, ∠Z ≅ ∠B

Therefore ΔXYZ ∼ ΔACB are  similar triangles because it has its corresponding sides to be proportional and its corresponding angles to be congruent.

Note:

sin ∠X = 5/5.59

sin ∠X = YZ/XY

YZ = 5  seen in ΔXYZ

XZ = 5.59 seen in hypotenuse of ΔXYZ

Then one need to Calculate the length of one aspect of XY:

XY = √((5.59)2 - 52)

= 2.4996

Note CB/YZ = 2

CD = 2*YZ = 2 x 5

= 10

AC/XY = 2

AC = 2* XY

= 2 x 2.4996

= 4.999

Learn more about dilation from:

brainly.com/question/27517432

#SPJ1

7 0
2 years ago
HELPPPPPPPPPP!!!!!!!!!!
juin [17]

Answer:

The last one

Step-by-step explanation:

measure angle 2 and 6 to see if congruent

4 0
3 years ago
What is another way to write 3427.68 divided by 54
skad [1K]
3427.68/54 could be another way
4 0
3 years ago
Read 2 more answers
HELP PLZ ILL MAKE YOU BRAINLEIST
klemol [59]

Answer:

depends on the force acting on the two objects. For the gravitational force the formula is P.E. = mgh, where m is the mass in kilograms, g is the acceleration due to gravity (9.8 m / s2 at the surface of the earth) and h is the height in meters.

Step-by-step explanation:

7 0
3 years ago
student randomly receive 1 of 4 versions(A, B, C, D) of a math test. What is the probability that at least 3 of the 5 student te
alexdok [17]

Answer:

1.2%

Step-by-step explanation:

We are given that the students receive different versions of the math namely A, B, C and D.

So, the probability that a student receives version A = \frac{1}{4}.

Thus, the probability that the student does not receive version A = 1-\frac{1}{4} = \frac{3}{4}.

So, the possibilities that at-least 3 out of 5 students receive version A are,

1) 3 receives version A and 2 does not receive version A

2) 4 receives version A and 1 does not receive version A

3) All 5 students receive version A

Then the probability that at-least 3 out of 5 students receive version A is given by,

\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{3}{4}\times \frac{3}{4}+\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{3}{4}+\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}

= (\frac{1}{4})^3\times (\frac{3}{4})^2+(\frac{1}{4})^4\times (\frac{3}{4})+(\frac{1}{4})^5

= (\frac{1}{4})^3\times (\frac{3}{4})[\frac{3}{4}+\frac{1}{4}+(\frac{1}{4})^2]

= (\frac{3}{4^4})[1+\frac{1}{16}]

= (\frac{3}{256})[\frac{17}{16}]

= 0.01171875 × 1.0625

= 0.01245

Thus, the probability that at least 3 out of 5 students receive version A is 0.0124

So, in percent the probability is 0.0124 × 100 = 1.24%

To the nearest tenth, the required probability is 1.2%.

4 0
3 years ago
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