Answer:
The standard deviation for the mean weigth of Salmon is 2/3 lbs for restaurants, 2/7 lbs for grocery stores and 1/4 lbs for discount order stores.
Step-by-step explanation:
The mean sample of the sum of n random variables is
If 
are indentically distributed and independent, like in the situation of the problem, then the variance of 
will be the sum of the variances, in other words, it will be n times the variance of 
.
However if we multiply this mean by 1/n (in other words, divide by n), then we have to divide the variance by 1/n², thus 
and as a result, the standard deviation of 
is the standard deviation of divided by 
.
Since the standard deviation of the weigth of a Salmon is 2 lbs, then the standard deviations for the mean weigth will be:
- Restaurants: We have boxes with 9 salmon each, so it will be
- Grocery stores: Each carton has 49 salmon, thus the standard deviation is
- Discount outlet stores: Each pallet has 64 salmon, as a result, the standard deviation is
We conclude that de standard deivation of the mean weigth of salmon of the types of shipment given is: 2/3 lbs for restaurants, 2/7 lbs for grocery stores and 1/4 lbs for discount outlet stores.
Answer:
41.40
Step-by-step explanation: 36*.15=5.40, 36+5.40=41.40
<h3>Given</h3>
A(-3, 1), B(4, 5)
<h3>Find</h3>
coordinates of P on AB such that AP/PB = 5/2
<h3>Solution</h3>
AP/PB = 5/2 . . . . . desired result
2AP = 5PB . . . . . . multiply by 2PB
2(P-A) = 5(B-P) . . . meaning of the above
2P -2A = 5B -5P . . eliminate parentheses
7P = 2A +5B . . . . . collect P terms
P = (2A +5B)/7 . . . .divide by the coefficient of P
P = (2(-3, 1) +5(4, 5))/7 . . . . substitute the given points
P = (-6+20, 2+25)/7 . . . . . . simplify
P = (2, 3 6/7)
Answer:
(3,4)
Step-by-step explanation:
The system of equations is:
x+6y=27
7x-3y=9.
I looked up "metodo de igualacion". It is basically American for doing substitution.
However, the only difference is you are asked to solve both equations for a variable.
The first equation looks easy to solve for x. So I'm going to solve both equations for x.
x+6y=27
Subtract 6y on both sides:
x =-6y+27
7x-3y=9
Add 3y on both sides:
7x =3y+9
Divide both sides by 7:
x =3/7 y +9/7
So both equations are solved for x. You want to find when the x's are the same because you are looking for a common amongst the lines given.
So we have
-6y+27=3/7 y +9/7
I hate the fractions honestly so I'm going to multiply both sides by 7 so they will no longer be for now:
-42y+189=3y + 9
Now add 42y on both sides:
189=45y+9
Subtract 9 on both sides:
180=45y
Divide both sides by 45:
4=y
If 4=y, then y=4.
So now once we have obtain 4 for y, we will use one of the equations given along with it to find x. Just choose one. Choose the easier looking one to you.
I like the x=-6y+27 with y=4.
So replace y with giving you:
x=-6(4)+27
x=-24+27
x=3
So the solution is (x,y)=(3,4).
x=3 and y=4.
X=4 and x=6
I suppose this is the correct answer.
