Well if you roll two dice and you land them both on 2 then you get 4 hope this helps :)
Answer:
The answer is
Step-by-step explanation:
Solution:
Let we first name the Triangle as Δ ABC and ray BD as a bisector of ∠B
as shown in the figure below.
As ray BD is the bisector of angle B so, by Angle bisector theorem property we have
∴
∴
∴
∴ final answer
Answer:
A) The minimum required diameter of the brass shaft D₁ = 0.00176 m
B) The minimum required diameter of the aluminium shaft D₂ = 0.00142 m
Step-by-step explanation:
<u>Data:</u>
A compound shaft has two segments made of brass and aluminium
Allowable shear stress of Brass = 69 MPa.
allowable sheer stress of Aluminium = 86 MPa.
Torque TC = 23900 N-m
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<u>Find</u>: Minimum required diameter of the brass D₁ and Auminium D₂
<u>Solution</u>: see attached picture for workings that shows the break down of the minimum diameter for each segment of the shaft.