Question

Solve y = f(x) = (2x+1)^1/2 & g(x) = x-1

Answer 1

Answer:

f(x) = $x = \frac{y^{2} - 1}{2}$

g(x) = 1

Step-by-step explanation:

y = (2x + 1)^1/2

$y^{2} = 2x + 1$

$y^{2} - 1 = 2x$

$\frac{y^{2} - 1}{2} = x$

y = x - 1

y + 1 = x