For this case what we must do is a composition of functions which will be given by:
m (x) = 4x - 11
n (x) = x - 10
We have then:
m [n (x)] = 4 (x - 10) - 11
Rewriting the function:
m [n (x)] = 4x - 40 - 11
m [n (x)] = 4x - 51
Answer:
a. m [n (x)] = 4x - 51
De Moivre's theorem uses this general formula z = r(cos α + i<span> sin α) that is where we can have the form a + bi. If the given is raised to a certain number, then the r is raised to the same number while the angles are being multiplied by that number.
For 1) </span>[3cos(27))+isin(27)]^5 we first apply the concept I mentioned above where it becomes
[3^5cos(27*5))+isin(27*5)] and then after simplifying we get, [243 (cos (135) + isin (135))]
it is then further simplified to 243 (-1/ √2) + 243i (1/√2) = -243/√2 + 243/<span>√2 i
and that is the answer.
For 2) </span>[2(cos(40))+isin(40)]^6, we apply the same steps in 1)
[2^6(cos(40*6))+isin(40*6)],
[64(cos(240))+isin(240)] = 64 (-1/2) + 64i (-√3 /2)
And the answer is -32 -32 √3 i
Summary:
1) -243/√2 + 243/√2 i
2)-32 -32 √3 i
2/4 is shorter distance. I think. Hope its helps !!!!!!!
Answer:
( 3x -2)
Step-by-step explanation:
6x^2 – 7x + 2
We know that the constant only has factors of 1 and 2
Since the middle term is negative we know that that we are subtracting
A negative times a negative is positive for the final term
A negative plus a negative is negative for the middle term
( -1 ) ( -2)
We have to determine how to break up 6x^2
1x * 6x
2x*3x
3x*2x
6x*1x
We are given that one factor is 2x-1
( 2x -1 ) ( -2)
That means the other factor of 6x^2 is 3x ( 2x*3x)
( 2x -1 ) ( 3x -2)
