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Maru [420]
4 years ago
12

The graph shows the number of handbags that Mandy made in one day. What are the variables? Describe how the variables are relate

d at various points on the graph.

Mathematics
2 answers:
klio [65]4 years ago
7 0
The variables are the number of handbags and the time.
Margaret [11]4 years ago
5 0
<h2>1. The variables</h2>

A graph is a picture that uses lines or curves to show the relationship between numbers or measurements that change. So, the graph in this problem indicates the number of handbags that Mandy made in one day. A variable is a quantity that may change according to the context of a mathematical problem or experiment. In this problem, we have two variables that are:


x = Time

y = Number of Handbags


<h2>2. Relationship between variables</h2>

As we said, this graph shows the Mandy's Handbags. From the graph, we can see that the number of handbags increases constantly at a regular interval. Until the time when he stopped making new handbags for the day. It is important to say that<em> time</em> is the independent variable while <em>the number of handbags</em> is the dependent variable, which is dependent on time.

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Step-by-step explanation:

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A manufacturer of Christmas light bulbs knows that 10% of these bulbs are defective. It is known that light bulbs are defective
andriy [413]

Answer:

(a) P(X \leq 20) = 0.9319

(b) Expected number of defective light bulbs = 15

(c) Standard deviation of defective light bulbs = 3.67

Step-by-step explanation:

We are given that a manufacturer of Christmas light bulbs knows that 10% of these bulbs are defective. It is known that light bulbs are defective independently. A box of 150 bulbs is selected at random.

Firstly, the above situation can be represented through binomial distribution, i.e.;

P(X=r) = \binom{n}{r} p^{r} (1-p)^{2} ;x=0,1,2,3,....

where, n = number of samples taken = 150

            r = number of success

           p = probability of success which in our question is % of bulbs that

                  are defective, i.e. 10%

<em>Now, we can't calculate the required probability using binomial distribution because here n is very large(n > 30), so we will convert this distribution into normal distribution using continuity correction.</em>

So, Let X = No. of defective bulbs in a box

<u>Mean of X</u>, \mu = n \times p = 150 \times 0.10 = 15

<u>Standard deviation of X</u>, \sigma = \sqrt{np(1-p)} = \sqrt{150 \times 0.10 \times (1-0.10)} = 3.7

So, X ~ N(\mu = 15, \sigma^{2} = 3.7^{2})

Now, the z score probability distribution is given by;

                Z = \frac{X-\mu}{\sigma} ~ N(0,1)

(a) Probability that this box will contain at most 20 defective light bulbs is given by = P(X \leq 20) = P(X < 20.5)  ---- using continuity correction

    P(X < 20.5) = P( \frac{X-\mu}{\sigma} < \frac{20.5-15}{3.7} ) = P(Z < 1.49) = 0.9319

(b) Expected number of defective light bulbs found in such boxes, on average is given by = E(X) = n \times p = 150 \times 0.10 = 15.

Standard deviation of defective light bulbs is given by = S.D. = \sqrt{np(1-p)} = \sqrt{150 \times 0.10 \times (1-0.10)} = 3.67

8 0
3 years ago
WORTH 50 POINTS please help
Sophie [7]

Answer: not sure but I think the equation would be x=1 sorry

Step-by-step explanation:

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