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nadezda [96]
3 years ago
12

Before tax, and miscellaneous charges, Jason's cell phone bill is $100 per month plus $0.15 for every text message that he sends

or receives. Which expression represents his cell phone bill for any given month?
Mathematics
2 answers:
dexar [7]3 years ago
5 0
0.15x + 100
x representing amount of text messages sent or received
Luda [366]3 years ago
3 0

Answer:

0.15x+100.

Step-by-step explanation:

Let x represent number of texts.

We have been given that Jason's cell phone bill is $100 per month plus $0.15 for every text message that he sends or receives.

Since cost of sending or receiving each text is $0.15, so cost of receiving and sending x texts would be 0.15x.

The total cost of bill would be fixed charge $100 plus cost of receiving and sending x texts. Therefore, Jason's cell phone bill would be 0.15x+100.

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pshichka [43]

Answer:

  9.5%

Step-by-step explanation:

As a percentage of sales, Harris's earnings were ...

  447/89400 × 100% = 0.5%

more than George's.

Harris's commission rate must be 9% + 0.5% = 9.5%.

7 0
3 years ago
How many real solutions does the equation y2− 8y + 16 = 0 have?
saveliy_v [14]
We can solve this equation by completing the square. Notice that 4*2=8 and 4^{2}=16. Therefore, we can turn y^{2}-8y+16=0 into (y-4)^{2}=0. y, in this equation, only has one real solution: 4. So your answer would be (B).
4 0
4 years ago
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pentagon [3]

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The standard deviations also indicate that the second lake has some even deeper spots, and even the shallower spots of the second lake are about the same as the shallow spots of the first lake.

Step-by-step explanation:

7 0
3 years ago
You earn 15n15n dollars for mowing nn lawns. how much do you earn for mowing one lawn? seven lawns?
kvasek [131]
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6 0
4 years ago
Write the given roots to quadraatic equation
german

Answer:

It's like solving a quadratic, but in reverse, and in this case you'll arrive at x2+x−12=0

Explanation:

We're going to go "backwards" with this problem - normally we're asked to take a quadratic equation and find the roots. So we'll do what we normally do, but in reverse:

Let's start with the roots:

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