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mash [69]
4 years ago
15

How many real solutions does the equation y2− 8y + 16 = 0 have?

Mathematics
1 answer:
saveliy_v [14]4 years ago
4 0
We can solve this equation by completing the square. Notice that 4*2=8 and 4^{2}=16. Therefore, we can turn y^{2}-8y+16=0 into (y-4)^{2}=0. y, in this equation, only has one real solution: 4. So your answer would be (B).
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