3 years ago

How many real solutions does the equation y2− 8y + 16 = 0 have?

1 answer:

4 0

We can solve this equation by completing the square. Notice that $4*2=8$ and $4^{2}=16$ . Therefore, we can turn $y^{2}-8y+16=0$ into $(y-4)^{2}=0$ . y, in this equation, only has one real solution: 4. So your answer would be (B).

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3 0

3 years ago

The drama club was selecting which carnival booths to sponsor at the fall carnival from a list of nine. How many different ways

denis-greek [22]

Answer:

Option B

Step-by-step explanation:

Here we have to apply " combination and permutation. " It is given that the drama club had to choose three booths from a selection of 9, considering the possible ways to choose so. This is a perfect example of combination. In nCr, n corresponds to 9, respectively r corresponds to 3.

$\mathrm{n\:choose\:r},\\nCr=\frac{n!}{r!\left(n-r\right)!},\\\\\frac{9!}{3!\left(9-3\right)!} =\\\frac{9!}{3!\cdot \:6!} =\\\\\frac{9\cdot \:8\cdot \:7}{3!} =\\\frac{504}{6} =\\\\84\\\\Solution = Option B$