Question

How many real solutions does the equation y2− 8y + 16 = 0 have?

Answer 1

We can solve this equation by completing the square. Notice that $4*2=8$ and $4^{2}=16$. Therefore, we can turn $y^{2}-8y+16=0$ into $(y-4)^{2}=0$. y, in this equation, only has one real solution: 4. So your answer would be (B).