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mash [69]
4 years ago
15

How many real solutions does the equation y2− 8y + 16 = 0 have?

Mathematics
1 answer:
saveliy_v [14]4 years ago
4 0
We can solve this equation by completing the square. Notice that 4*2=8 and 4^{2}=16. Therefore, we can turn y^{2}-8y+16=0 into (y-4)^{2}=0. y, in this equation, only has one real solution: 4. So your answer would be (B).
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Step-by-step explanation:

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katovenus [111]

Answer:

numbers\ of\ cars \geq \frac{75000}{price\ of\ the\ car}

Step-by-step explanation:

Hello, I can help you with this

Step 1

define

The minimum weekly commission earned to be a STAR sales person is $9000, let's name this value as M

if Sandra receives a 12% commisions of the sale of all cars, then that 12% must be equal or higher than 9000 in order to become a STAR sales person

Step 2

using a rule of three find the 100%

if

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the ratio is

\frac{12}{9000}=\frac{100}{x}\\

Now, solve for x

\frac{12}{9000}=\frac{100}{x}\\\\\frac{12*x}{9000}=\frac{100}\\\\{12x}=9000*100\\\\12x=900000\\x=\frac{900000}{12}\\ x=75000\\

so, Sandra must sell a minimun of $75000

Now, to give a response, we need to asume a only price for every car(p).

now, in matemathical terms.

the minimun number of cars she must to sell is

minum number of cars sandra has to sell to become a STAR sales person

is \frac{75000}{price\ of\ the\ car} \\

\frac{75000}{price\ of\ the\ car} \\

now, price of the car* number of the car = 75000

where

numbers\ of\ cars \geq \frac{75000}{price\ of\ the\ car}

Have a nice day

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Step-by-step explanation:

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