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Yuki888 [10]
4 years ago
9

Name

Mathematics
1 answer:
N76 [4]4 years ago
7 0

The temperature drop during one day is 610 °C, If the temperature on mercury can reach 430  °C and the night time temperature can drop to -180  °C.

Step-by-step explanation:

The given is,

          Daytime temperature on Mercury  can reach 430 °C

          Nighttime  temperature can drop to -180 °C

Step:1

          For temperature drop of an mercury,

                     = Temperature at Daytime - Temperature at Nighttime

                     = 430 - ( - 180 )

                     = 430 +180

                     = 610

         Drop of temperature in mercury = 610 °C

Result:

         Thus the temperature drop during one day is 610 °C, If the temperature on mercury can reach 430  °C and the night time temperature can drop to -180  °C.

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timofeeve [1]

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Step-by-step explanation:

THIS IS THE COMPLETE QUESTION

In 1 h the minute hand on a clock moves through a complete circle, and the hour hand moves through 1 12 of a circle. Through how many radians do the minute hand and the hour hand move between 1:00 p.m. and 1:45 p.m. (on the same day)?

SOLUTION

✓If the minute hand on a clock moves through complete circle in 1 hour, then it means that it goes through a circle and angle of circle in radians is 2π.

Between 1:00 p.m. and 1:45pm in the same day we have 45 minutes i.e (1.45 pm -1pm)

Within the 1hour minutes, the hand can move with complete cycle of 2π radians

Then At time t= 45minutes

Angle through the circle at 45 minutes= 45/60 ×2π radians

= 3π/2 radians

And if the hour hand goes through a complete cycle 1/12 as told in the question we have 1/2 × 2π radians

For t=45 minutes

Then 1/12 × 2π ×45/60

= π/8 radians

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Step-by-step explanation:

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