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Zielflug [23.3K]
2 years ago
9

the following data values represent a population. what is the variance of the values? 17, 5, 11, 1, 11

Mathematics
1 answer:
Vladimir [108]2 years ago
4 0
Variance = summation of (x - mean)^2 all divided by the number of dataset.
mean = (17 + 5 + 11 + 1 + 11)/5 = 9

Variance = [(17 - 9)^2 + (5 - 9)^2 + (11 - 9)^2 + (1 - 9)^2 + (11 - 9)^2]/5 = (8^2 + (-4)^2 + 2^2 + (-8)^2 + 2^2}/5 = (64 + 16 + 4 + 64 + 4)/5 = 152/5 = 30.4
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3 years ago
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How to solve this problem
Agata [3.3K]
So first, you have to get two of the same variables to cancel out. Let's do this for x. In order for the x's to cancel out, we could multiply the bottom problem by 2.
(2) 3x-6y=24
After multiplying all the numbers by 2, you get the equation 6x-12y=48
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-6x+2y=12
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Now you can add them. The x variables cancel out, so you are left with the y variable.
2y+-12y=-10y and 12+48=60
Then you would divide 60 by -10 to get y=-6.
You would plug the answer for y into one of the original equations, lets do the top one. -6x+2y=12 becomes -6x+2(-6)=12
You'd multiply the 2 and -6 to get -12 so the equation is
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The negative 12 turn positive and you add to both sides to get the -6x alone.
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Then divide 24 by -6
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7 0
3 years ago
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