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riadik2000 [5.3K]
3 years ago
5

What is the value of the 4 in 284.6172​

Mathematics
2 answers:
Feliz [49]3 years ago
7 0

Answer:

ones

Step-by-step explanation:

lesya [120]3 years ago
7 0

Answer:

The value of 4 in 234.6172 is the ones places

Step-by-step explanation:

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40% of the students in Jody's class
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40% = 40/100 = 0.40
Find 40% of 20
20 * 0.40 = 8
Solution: 8 students traveled
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What is -√12+3√3? I need to know.
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Answer:

√3

Step-by-step explanation:

√12=2√3

-2√3+3√3 = √3

Use calculator to estimate if necessary: 1.7320508075688773

4 0
3 years ago
Read 2 more answers
On any given day, the probability that a large local river is polluted by carbon tetrachloride is 0.12. Each day, a test is cond
babymother [125]

Answer:

a) 0.2416

b) 0.4172

c) 0.0253

Step-by-step explanation:

Since the result of the test should be independent of the time , then the that the test number of times that test proves correct is independent of the days the river is correct .

denoting event a A=the test proves correct and B=the river is polluted

a) the test indicates pollution when

- the river is polluted and the test is correct

- the river is not polluted and the test fails

then

P(test indicates pollution)= P(A)*P(B)+ (1-P(A))*(1-P(B)) = 0.12*0.84+0.88*0.16 = 0.2416

b) according to Bayes

P(A∩B)= P(A/B)*P(B) → P(A/B)=P(A∩B)/P(B)

then

P(pollution exists/test indicates pollution)=P(A∩B)/P(B) = 0.84*0.12 / 0.2416 = 0.4172

c) since

P(test indicates no pollution)= P(A)*(1-P(B))+ (1-P(A))*P(B) = 0.84*0.88+  0.16*0.12 = 0.7584

the rate of false positives is

P(river is polluted/test indicates no pollution) = 0.12*0.16 / 0.7584 = 0.0253

4 0
3 years ago
On Monday Ravi drives for 4 hours.
tensa zangetsu [6.8K]

Answer:

Step-by-step explanation:

On Monday Ravi drives for 4 hours.

His average speed is 30 mph.

How far does Ravi drive on Monday?

4 0
3 years ago
Read 2 more answers
Dividing rational expressions
Galina-37 [17]
\bf \textit{difference of squares}
\\ \quad \\
(a-b)(a+b) = a^2-b^2\qquad \qquad 
a^2-b^2 = (a-b)(a+b)\\\\
-----------------------------\\\\
\cfrac{x+3}{x^2-2x}\cdot \cfrac{(x-2)^2}{x^2-9}\implies \cfrac{x+3}{x^2-2x}\cdot \cfrac{(x-2)(x-2)}{x^2-3^2}
\\\\\\
\cfrac{x+3}{x(x-2)}\cdot \cfrac{(x-2)(x-2)}{x^2-3^2}\implies \cfrac{\underline{x+3}}{x\underline{(x-2)}}\cdot \cfrac{\underline{(x-2)}(x-2)}{(x-3)\underline{(x+3)}}
\\\\\\
\cfrac{x-2}{x(x-3)}\iff\cfrac{x-2}{x^2-3x}
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3 years ago
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