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4 years ago

Find three consecutive integers so that the

Mathematics

1 answer:

Ludmilka [50]4 years ago

6 0

Answer:

11, 12, and 13.

Step-by-step explanation:

11 + 12 = 23, and 23 is 10 more than 13. I figured this out with process of elimination.

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For the math experts

slamgirl [31]

Answer:

45 cause any value inside mod function always return to postive

8 0

3 years ago

Which of the following can you determine, when you use deduction and start from a given set of rules and conditions? O A. What m

snow_tiger [21]

Answer:

Its C it must be true

Step-by-step explanation:

5 0

2 years ago

The ratio of the girls to the total number of students in class is 47 how many students are girls in the class has 21 students a

Airida [17]

You can cross multiply to get 4 * 21 = 7x

84 = 7x; divide both sides by 7

12 = x so the number 12 will go in the blank (12 girls)

4 0

4 years ago

Read 2 more answers

Arrange the equations in the correct sequence to rewrite the formula for displacement, , to find a. In the formula, d is displac

OverLord2011 [107]

Answer:

2(d-vt)=-at^2

a=2(d-vt)/t^2

at^2=2(d-vt)

Step-by-step explanation:

Arrange the equations in the correct sequence to rewrite the formula for displacement, d = vt—1/2at^2 to find a. In the formula, d is

displacement, v is final velocity, a is acceleration, and t is time.

Given the formula for calculating the displacement of a body as shown below;

d=vt - 1/2at^2

Where,

d = displacement

v = final velocity

a = acceleration

t = time

To make acceleration(a), the subject of the formula

Subtract vt from both sides of the equation

d=vt - 1/2at^2

d - vt=vt - vt - 1/2at^2

d - vt= -1/2at^2

2(d - vt) = -at^2

Divide both sides by t^2

2(d - vt) / t^2 = -at^2 / t^2

2(d - vt) / t^2 = -a

a= -2(d - vt) / t^2

a=2(vt - d) / t^2

2(vt-d)=at^2

4 0

3 years ago

A college conducts a common test for all the students. For the Mathematics portion of this test, the scores are normally distrib

Jet001 [13]

Using the normal distribution, it is found that 58.97% of students would be expected to score between 400 and 590.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean $\mu$ and standard deviation $\sigma$ is given by:

$Z = \frac{X - \mu}{\sigma}$

The z-score measures how many standard deviations the measure is above or below the mean.

Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

The mean and the standard deviation are given, respectively, by:

$\mu = 502, \sigma = 115$

The proportion of students between 400 and 590 is the <u>p-value of Z when X = 590 subtracted by the p-value of Z when X = 400</u>, hence:

X = 590:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{590 - 502}{115}$

Z = 0.76

Z = 0.76 has a p-value of 0.7764.

X = 400:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{400 - 502}{115}$

Z = -0.89

Z = -0.89 has a p-value of 0.1867.

0.7764 - 0.1867 = 0.5897 = 58.97%.

58.97% of students would be expected to score between 400 and 590.

More can be learned about the normal distribution at brainly.com/question/27643290

#SPJ1

6 0

2 years ago