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sp2606 [1]
3 years ago
7

Emil bought a camera for $268.26, including tax. He made a down payment of $12.00 and paid the balance in 6 equal monthly paymen

ts. What was Emil’s monthly payment for this camera?
Mathematics
2 answers:
IrinaVladis [17]3 years ago
8 0
Emils monthly down payment for the camera was $72.00. 12 × 6 = 72
iragen [17]3 years ago
7 0
The total cost of the camera is $268.26

A down payment of $12 was paid so he now owes $256.26

Every 6 months Emil has to pay:
256.26 / 6 = 42.71
Therefore, each moth, Emil has to pay $42.71 
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Students who attend Anytown College pay either in-state or out-of-state tuition, depending on where they reside. The amount, I,
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3 years ago
Find the vertex I’d this parabola y=-2x^2-4x+4
mamaluj [8]

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  (-1, 6)

Step-by-step explanation:

A graphing calculator shows the vertex to be (x, y) = (-1, 6).

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You can also find it by putting the equation into vertex form.

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5 0
3 years ago
You want to place a towel bar that is 24 1/4 centimeters long in the center of a door that is 70 1/3 centimeters wide. How far s
Aleksandr [31]

Answer:

The towel bar should be placed at a distance of 23\frac{1}{24}\ cm from each edge of the door.

Step-by-step explanation:

Given:

Length of the towel bar = 24\frac14\ cm

Now given length is in mixed fraction we will convert in fraction.

To Convert mixed fraction into fraction Multiply the whole number part by the fraction's denominator, then Add that to the numerator, then write the result on top of the denominator.

24\frac14\ cm can be Rewritten as \frac{97}{4}\ cm

Length of the towel bar =  \frac{97}{4}\ cm

Length of the door = 70 \frac13\ cm

70 \frac13\ cm can be Rewritten as \frac{211}{3}\ cm

Length of the door = \frac{211}{3}\ cm

We need to find the distance bar should be place at from each edge of the door.

Solution:

Let the distance of bar from each edge of the door be 'x'.

 So as we placed the towel bar in the center of the door it divides into two i.e. '2x'

Now we can say that;

\frac{97}{4}+2x=\frac{211}{3}\\\\2x=\frac{211}{3}-\frac{97}{4}

Now we will take LCM to make the denominators common we get;

2x=\frac{211\times4}{3\times4}-\frac{97\times3}{4\times3}\\\\\\2x= \frac{844}{12}+\frac{281}{12}

Now denominators are common so we will solve the numerators.

2x =\frac{844-291}{12}\\\\2x=\frac{553}{12}\\\\x=\frac{553}{12\times2} =\frac{553}{24}

Or x=23\frac{1}{24}\ cm

Hence The towel bar should be placed at a distance of 23\frac{1}{24}\ cm from each edge of the door.

8 0
3 years ago
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