For each <em>x</em> in the interval 0 ≤ <em>x</em> ≤ 5, the shell at that point has
• radius = 5 - <em>x</em>, which is the distance from <em>x</em> to <em>x</em> = 5
• height = <em>x</em> ² + 2
• thickness = d<em>x</em>
and hence contributes a volume of 2<em>π</em> (5 - <em>x</em>) (<em>x</em> ² + 2) d<em>x</em>.
Taking infinitely many of these shells and summing their volumes (i.e. integrating) gives the volume of the region:

3.04 , 3.14 , 3.4 , 4.03 , 4.4
Answer:
-3.1, -3.2, -3.3, -3.4, -3.5, -3.6
Step-by-step explanation:
Answer:
me neither :c
Step-by-step explanation: