Math!! Who knows answers???
1 answer:
You might be interested in
Aw yis
take the coefients and put them in rows
![\left[\begin{array}{ccc}4&5&|-7\\3&-6&|24\end{array}\right]](https://tex.z-dn.net/?f=%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D4%265%26%7C-7%5C%5C3%26-6%26%7C24%5Cend%7Barray%7D%5Cright%5D%20)
divide 2nd row by 3
![\left[\begin{array}{ccc}4&5&|-7\\1&-2&|8\end{array}\right]](https://tex.z-dn.net/?f=%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D4%265%26%7C-7%5C%5C1%26-2%26%7C8%5Cend%7Barray%7D%5Cright%5D%20)
multiply 2nd row by -4 and add to top one
![\left[\begin{array}{ccc}0&13&|-39\\1&-2&|8\end{array}\right]](https://tex.z-dn.net/?f=%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D0%2613%26%7C-39%5C%5C1%26-2%26%7C8%5Cend%7Barray%7D%5Cright%5D%20)
divide top row by 13
![\left[\begin{array}{ccc}0&1&|-3\\1&-2&|8\end{array}\right]](https://tex.z-dn.net/?f=%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D0%261%26%7C-3%5C%5C1%26-2%26%7C8%5Cend%7Barray%7D%5Cright%5D%20)
multiply top row by 2 and add to bottom row
![\left[\begin{array}{ccc}0&1&|-3\\1&0&|2\end{array}\right]](https://tex.z-dn.net/?f=%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D0%261%26%7C-3%5C%5C1%260%26%7C2%5Cend%7Barray%7D%5Cright%5D%20)
x=2
y=-3
take the coefients and put them in rows
divide 2nd row by 3
multiply 2nd row by -4 and add to top one
divide top row by 13
multiply top row by 2 and add to bottom row
x=2
y=-3
The given graph is a downward parabola.
The roots of the equation is -2 and -8, and the vertex is (-5,7).
The general root form of parabola will be,
a(x-(-2))(x-(-8))=a(x+2)(x+8).
The value of a can be determined from the coordinate of vertex,
Thus, the required quadratic is,
The value of f(-6) can be determined as,
Thus, the requried value of f(-6) is 6.22.
