There are 12 cards with different letters & patterns. The probability of randomly choosing [random card] is #[random card]/total cards.
Think of that as ratio as a %chance or probability of written as P(X). The question says to write the %chance as a fraction.
1) 2/12 = 1/6
2) 2/12 = 1/6
3) 0/12 = 0
4) 12/12 = 1
5) This is tricky. M & T would imply one card with both letters on it. 0/12 = 0
6) 4/12 = 1/3
7) 6/12 = 1/2
8) 5/12
9) 3/12 = 1/4
10) 8/12 = 2/3
11) 10/12 = 5/6
12) Odds = [favorable]:[unfavorable] = 5:7
Answer:
1/2 mile
Step-by-step explanation:
(1/8)*4 = 1/2 mile
Congruent triangle are the same shape and same size exactly
Answer:
this is my attempt, it might not be right, so please dont be mad if wrong
Step-by-step explanation:
27 * x^3 = 6561x-5 , 49x + 1 = 117649x-2
The simplest interpretation would go a little something like this:
We know that we want the total donation amount to be more than $7,900, so we can set up this inequality to begin with
![D \ \textgreater \ 7,900](https://tex.z-dn.net/?f=D%20%5C%20%5Ctextgreater%20%5C%207%2C900)
Where
D is the total donations raised (in dollars). How do we find D? Well, we just add up the total number of table reservations sold and the total number of single tickets sold. If we let
r stand for the number of reservation tickets and
s stand for the number of single tickets, then we have
![D=540r+34s](https://tex.z-dn.net/?f=D%3D540r%2B34s)
So, the inequality representing this situation would be
![540r+34s\ \textgreater \ 7,900](https://tex.z-dn.net/?f=540r%2B34s%5C%20%5Ctextgreater%20%5C%207%2C900)
And that would probably be fine for this problem.
<span><em>Footnote:</em>
</span>Of course, if this were a real-life scenario, we'd need to take some additional details into account: How many tables do we have? How many people can be seated at each table?