Answer:
The estimation for the proportion of tenth graders reading at or below the eighth grade level is given by:
And the 90% confidence interval would be given (0.131;0.169).
Step-by-step explanation:
We have the following info given:
represent the sampel size slected
number of students who read above the eighth grade level
The estimation for the proportion of tenth graders reading at or below the eighth grade level is given by:
The confidence interval for the proportion would be given by this formula
For the 90% confidence interval the significance is 
and 
, with that value we can find the quantile required for the interval in the normal standard distribution and we got.
And replacing into the confidence interval formula we got:
And the 90% confidence interval would be given (0.131;0.169).
Answer:
c
Step-by-step explanation:
2.4 on the number line is B
Answer:
If your weekly allowance is 5, then for Christmas week your allowance was 15, then your allowance went up by: 5 =3 - 1 = 2 x 100 =200%.
N = number of compounding periods
Years = log (total / principal) / n * log (1 + rate / n)
Years = log (750 / 500) / 4 * log (1 + .025/n)
Years = log (1.5) / 4 * log (1<span><span>.00625)
</span>
</span> <span>Years = 0.17609125906 / 4 * 0.0027058933759
</span><span>Years = 0.17609125906
</span>
/
<span>
<span>
<span>
0.0108235735
</span>
</span>
</span>
Years =
<span>
<span>
<span>
16.2692348382
</span>
</span>
</span>
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