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3 years ago

Find the domain of the function:f (x) = 2x/x^2-4

Mathematics

1 answer:

denis23 [38]3 years ago

3 0

Answer:

see explanation

Step-by-step explanation:

The denominator of f(x) cannot be zero as this would make f(x) undefined. Equating the denominator to zero and solving gives the values that x cannot be.

x² - 4 = 0 ⇒ x² = 4 ⇒ x = ± 2 ← excluded values

domain : x ∈ R, x ≠ ± 2

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PLEASE HELP I've tried everything 30 points!

Luda [366]

Answer:

(x+2)1x-8)=0

x=-2 or x=8

Step-by-step explanation:

The given quadratic expression is

$2 {x}^{2} - 12x - 32$

We equate this expression to zero to get:

$2 {x}^{2} - 12x - 32 = 0$

Let us divide through by 2 to get:

${x}^{2} - 6x - 16 = 0$

Split the middle term to get:

${x}^{2} - 8x + 2x - 16 = 0$

Factor

${x}(x - 8) + 2(x - 8) = 0$

Factor further to get

$(x - 8)(x + 2) = 0$

The solution are

$x = - 2 \: and \: x = 8$

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kherson [118]

3x-4 = -10

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3x = -6

then you can divide it :

x = -6 : 3

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Find the domain of the function:f (x) = 2x/x^2-4​

Find the domain of the function:f (x) = 2x/x^2-4