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Stolb23 [73]
2 years ago
11

Easy 20 PTS PTS PTS PTS

Mathematics
1 answer:
Serhud [2]2 years ago
7 0

Answer:

Step-by-step explanation:

The trouble maker is √(x - 3).

If you try and put in (say) - 1 for x, what happens is that you are taking the square root of -1 - 3 = - 4. At this level of math, you can't take the square root of a number < 3. So that modified is what you put in the blank.

The domain for f(x) is all the real numbers larger than or equal to 3.

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The rectangle below has an area of 14x^4 + 6x^2 square meters. The width of the rectangle (in meters) is equal to the greatest c
julia-pushkina [17]

Answer:

w=2x^2 and l = (7x^2+3)

Step-by-step explanation:

The area of a rectangle is 14x^4+6x^2 which factors through GCF, by finding the greatest common monomial factor between the two.

14x^4+6x^2 = 2*7x^4 + 2*3x^2 = 2x^2(7x^2+3)

The length and width of the rectangle are w=2x^2 and l = (7x^2+3).

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4 years ago
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BigorU [14]

Answer:

what's the question tho?

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3 years ago
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Write a rule for the sequence. Then find the next three terms. 6, 8, 10, 12
BaLLatris [955]
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3 years ago
What is the area please<br><br> Troll answers will be reported from 3 different alts
umka2103 [35]

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If I'm not mistaken the correct answer would be 241.

Step-by-step explanation:

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<img src="https://tex.z-dn.net/?f=%20%5Cunderline%7B%20%5Cunderline%7B%20%5Ctext%7Bquestion%7D%7D%7D%20%3A%20" id="TexFormula1"
steposvetlana [31]

Answer:

See Below.

Step-by-step explanation:

In the given figure, AP = BP = PC.

And we want to prove that ∠ABC is a right angle.

Since AP = BP and BP = PC, we can create two isosceles triangles: ΔAPB and ΔCPB.

By the definition of isosceles triangles, in ΔAPB, ∠PAB and ∠PBA are equivalent. Let the measure of each of them be <em>x°</em>.

Likewise, in ΔCPB, ∠PCB and ∠PBC are equivalent.

And since AP = BP = PC, each of the angles∠PCB and ∠PBC will also be equivalent to <em>x°.</em>

<em />

And since the sum of the interior angles of a triangle total 180°, we acquire:

\angle PAB+\angle PBA+\angle PCB+\angle PBC=180

Since they are all equivalent:

4x=180

Hence:

x=45^\circ

∠ABC is the sum of ∠PBA and ∠PBC, each of which measures 45°. Hence:

\angle ABC=\angle PBA+\angle PBC=45+45=90^\circ

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