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Oliga [24]
3 years ago
10

You have a combination lock. Again, to open it you turn the dial to the right and stop at a first number; then you turn it to th

e left and stop at a second number. Finally, you turn the dial to the right and stop at a third number. Suppose you remember that the three numbers for your lock are 2, 9, and 5, but you don't remember the order in which the numbers occur. How many sequences of these three numbers are possible
Mathematics
1 answer:
tamaranim1 [39]3 years ago
6 0

Answer: 7

Step-by-step explanation:

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IgorC [24]

Answer:

Step-by-step explanation:

A

8 0
3 years ago
Which could be the value of the third side of a triangle with sides 3 and 4? A. 3 B. 7 C. 12 D. 20
LiRa [457]

Answer:

c

Step-by-step explanation:

3 0
3 years ago
A student records the number of hours that they have studied each of the last 23 days. They compute a sample mean of 2.3 hours a
natita [175]

Answer:

the standard deviation increases

Step-by-step explanation:

Let x₁ , x₂, .   .   .  , x₂₃ be the actual data observed by the student

The sample means  = x₁  +  x₂  +  .   .   .  , x₂₃ / 23

= \frac{x_1 +x_2 +...x_2_3}{23}

= 2.3hr

⇒\sum xi =2.3 \times 23 = 52.9hrs

let x₁ , x₂, .   .   .  , x₂₃  arranged in ascending order

Then x₂₃ was 10  and has been changed to 14

i.e x₂₃ increase to 4

Sample mean  = \frac{x_1 +x_2 +...x_2_3}{23}

\frac{52.9hrs + 4}{23} \\\\= \frac{56.9}{23} \\\\= 2.47

therefore, the new sample mean is 2.47

2) For the old data set

the median is x_1_2(th) values

[\frac{n +1}{2} ]^t^h value

when we use the new data set only x₂₃ is changed to 14

i.e the rest all observation remain unchanged

Hence, sample median = [{x_1_2]^t^h value remain unchange

sample median = 2.5hrs

The Standard deviation of old data set is calculated

=\sqrt{\frac{1}{n-1} \sum (xi - \bar x_{old})^2 } \\\\=\sqrt{\frac{1}{22}\sum ( xi - 2.3)^2 }---(1)

The new sample standard sample deviation is calculated as

= \sqrt{\frac{1}{n-1} \sum (xi-2.47)^2} ---(2)

Now, when we compare (1) and (2)  the square distance between each observation xi and old mean is less than the squared distance between each observation xi and the new mean.

Since,

(xi - 2.3)²  ∑ (xi - 2.47)²

Therefore , the standard deviation increases

6 0
3 years ago
Sean operates a lawn-cutting business. He charges $15 for a single lawn and $25 for a front and back lawn. Sean made $475 from 2
topjm [15]

The system of equations that models the given situation is given as follows:

  • x + y = 25.
  • 15x + 25y = 475.

<h3>What is a system of equations?</h3>

A system of equations is when two or more variables are related, and equations are built to find the values of each variable.

In this problem, the variables are given as follows:

  • Variable x: Number of single lawns cut.
  • Variable y: Number of front and back lawns cut.

He had 25 customers, hence:

x + y = 25.

He charges $15 for a single lawn and $25 for a front and back lawn, and made a total of $475, hence:

15x + 25y = 475

More can be learned about a system of equations at brainly.com/question/24342899

#SPJ1

3 0
2 years ago
I need help ASAP
ra1l [238]

Answer:

x =y-3 x=y-3 x=y-3 x=3

2 (y-3) + y= 12 => 3y= 18 => y= 6 => y=6

Step-by-step explanation:

6 0
2 years ago
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