Answer:
Picture below
Step-by-step explanation:
● 5/2 is 2.5 so just divide the space between 3 by 2
● for 1/3 divide the space between 0 and by 3
Answer:
<h3>2x-9y=1 is the correct answer of this question..</h3>
Thank you ☺️☺️
34.4448979592.........................
A (-2, 0)
B (4, 2)
so mid point (x,y) of 2 coordinates(x1,y1) and (x2,y2) is given as
(x,y) = ( (x1+x2)/2 , (y1+y2)/2)
= ( (-2+4)/2, (0+2)/2)
= (2/2, 2/2)
= (1, 1)
so your answer is (1,1) that is option 2
Answer:
The launch angle should be adjusted to 30.63°
Step-by-step explanation:
The range of a projectile which is the horizontal distance covered by the projectile can be expressed as;
R =(v^2 sin2θ)/g
Where
R = range
v = initial speed
θ = launch angle
g = acceleration due to gravity
For the case above. When the projectile is launched at angle 13° above the horizontal.
θ1 = 13
R1 = (v^2 sin2θ1)/g
R1 = (v^2 sin26°)/g ....1
For the range to double
R2 = (v^2 sin2θ)/g .....2
R2 = 2R1
Substituting R2 and R1
(v^2 sin2θ)/g = 2 × (v^2 sin26°)/g
Divide both sides by v^2/g
sin2θ = 2sin26
2θ = sininverse(2sin26)
θ = sininverse(2sin26)/2
θ = 30.63°
