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Leya [2.2K]
3 years ago
8

Write an expression that is equivalent to 3/5 (3y + 15). A. y + 9 B. y + 9 C.y + 15 D. y + 15

Mathematics
1 answer:
Alexus [3.1K]3 years ago
5 0
<span>Write an expression that is equivalent to 3/5 (3y + 15). A. y + 9 B. y + 9 C.y + 15 D. y + 15

</span>\dfrac{3}{5}( 3y+15) =   \dfrac{3*3y}{5}+ \dfrac{3*15}{5}=  \dfrac{9}{5}y+ \dfrac{45}{5}= \boxed{\dfrac{9}{5}y+9}<span>
</span>
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Answer:

Step-by-step explanation:

192

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Write the prime factorization of 500 in index form.
makvit [3.9K]

Answer:

2^{2} × 5^{3}

Step-by-step explanation:

500

= 2 x 250

= 2 x 10 x 25

= 2 x 2 x 5 x 5 x 5

= 2^{2} × 5^{3}

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If Z is the centroid of ∆LMN,WZ=4,ZN=14, and ZY = 10, find each missing measure
jeyben [28]

Answer:

ZM = 8

WM = 12

XZ = 7

XN = 21

LZ = 20

Step-by-step explanation:

The centroid of a triangle is the point of intersection of the midpoint of the each of the three sides of a triangle. The centroid of a triangle is located inside the triangle and it is known as the center of gravity.

The centroid theorem for a triangle states that the centroid of a triangle is located at 2/3 of the distance from the vertex of the triangle of the middle of the opposite side.

ZM = (2/3)WM (centroid theorem)

Therefore: WZ = (1/3)WM

WM = 3WZ = 3 * 4 = 12

ZM = (2/3) * WM = 2/3 * 12 = 8

ZN = (2/3)XN (centroid theorem)

XN = (3/2)ZN = 3/2 * 14 = 21

XN = 21

XZ + ZN = XN

XZ + 14 = 21

XZ = 7

LZ = (2/3)LY (centroid theorem)

Therefore: ZY = (1/3)LY

LY = 3ZY = 3 * 10 = 30

LZ = (2/3) * LY = 2/3 * 30 = 20

7 0
3 years ago
Find the value of x <br> A.)20<br> B.)55<br> C.)70<br> D.)38
Alex Ar [27]

Answer:

A.) 20

Step-by-step explanation:

These angles are complementary meaning they add up to 90°.

4x - 10 + x = 90

5x - 10 = 90

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3 years ago
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What is the surface area?
mash [69]

\large\bf{\underline{Answer:}}

‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎\large\bf{ = 3000 \:ft^2}

__________________________________________

\large\bf{\underline{Given:}}

  • A 3 dimensional figure with 5 sides
  • it has 3 rectangles with dimensions 28 ft and 25 ft
  • And 2 triangles with base =30 ft and height = 20 ft

\large\bf{\underline{To\: find:}}

  • Total surface area of figure

\large\bf{\underline{Therefore:}}

\bf{area \:of\: figure}

‎ㅤ{\bf = area \:of \:3\: rectangles + 2 \: triangles}

\large\bf{\underline{Formulas:}}

\boxed{\bf\pink{area\:of\: triangle= \frac{1}{2}\times base\times height}}

\boxed{\bf\pink{area\:of\: rectangle=length\times breadth}}

‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎\large\bf{= 3\times (28 \times 25 )+ 2(\frac{1}{2} \times 30 \times 20)}

‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎\large\bf{= 3 \times 800 + 2 \times 300}

‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎\large\bf{=2400+ 600}

‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎\large\bf{= 3000}

__________________________________________

\large\bf{\underline{Hence,}}

❒ Area of given figure

‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎\huge\mathfrak{= 3000\: ft^2}

5 0
3 years ago
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