Solve the right triangle.

On January 15, the end of the first pay period of the year North company employees earned 26,000 of sales salaries.

cluponka [151]

Step-by-step explanation:

Is this meant to be a question?

5 0

2 years ago

What's the pattern in 30 21 12 3 -6

Bas_tet [7]

$a_b=39 - 9b$

3 0

3 years ago

Read 2 more answers

Tj Max is offering a 15% discount on all items .The new price of a pair of jeans is 44.20 .What was the original price

dolphi86 [110]

Answer:

$52

Step-by-step explanation:

To find an original price you must find how much of a percent was left before the discount.

100% - 15% = 85%

You then take this percentage a DIVIDE it by the new price.

$44.20/85% = $52 is the original price of the jeans.

7 0

3 years ago

It is claimed that automobiles are driven on average more than 20,000 kilometers per year. To test this claim, 100 randomly sele

kow [346]

Answer:

$t=\frac{23500-20000}{\frac{3900}{\sqrt{100}}}=8.974$

$p_v =P(t_{99}>8.974)=9.43x10^{-15}$

If we compare the p value and the significance level given for example $\alpha=0.05$ we see that $p_v$ so we can conclude that we to reject the null hypothesis, and the actual mean is significantly higher than 20000.

Step-by-step explanation:

1) Data given and notation

$\bar X=23500$ represent the sample mean

$s=3900$ represent the sample standard deviation

$n=100$ sample size

$\mu_o =2000$ represent the value that we want to test

$\alpha$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to determine if the true mean is higher than 20000, the system of hypothesis would be:

Null hypothesis: $\mu \leq 2000$

Alternative hypothesis: $\mu > 2000$

We don't know the population deviation, so for this case is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{23500-20000}{\frac{3900}{\sqrt{100}}}=8.974$

Calculate the P-value

First we need to calculate the degrees of freedom given by:

$df=n-1=100-1=99$

Since is a one-side upper test the p value would be:

$p_v =P(t_{99}>8.974)=9.43x10^{-15}$

Conclusion

If we compare the p value and the significance level given for example $\alpha=0.05$ we see that $p_v$ so we can conclude that we to reject the null hypothesis, and the actual mean is significantly higher than 20000.

8 0

3 years ago

(UPE) Terremotos são eventos naturais que não têm relação com eventos climáticos extremos, mas podem ter consequências ambientai

Alex

Answer:

E= $10^{18}$ Joules

Step-by-step explanation:

1) Olá! Adicionando dados faltantes ao enunciado, como a fórmula dada: $M=\frac{2}{3}log(\frac{E}{E_{0}})\\$ e corrigindo a quantidade de Energia inicial: $10^{4,5}$ Vamos seguir aplicando a fórmula, lembrando das propriedades de logaritmo.

$M=\frac{2}{3}log(\frac{E}{E_{0}})\\9=\frac{2}{3}log(\frac{E}{10^{4,5}})*3\\27=2log(\frac{E}{10^{4.5}})\\log(\frac{E}{10^{4.5}})^{2}=27\\(\frac{E^{2}}{10^{9}})=10^{27}\\E^{2}=10^{27}*10^{9}\Rightarrow E=\sqrt{10^{36}}\rightarrow E=10^{18} Joules$

6 0

3 years ago