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GenaCL600 [577]
3 years ago
11

Please help me i will make it brainliest

Mathematics
2 answers:
Slav-nsk [51]3 years ago
7 0
I think it's -1 too I hope it's correct
nasty-shy [4]3 years ago
5 0
Your answer is -1. hope this helps
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A student has a monthly budget of $800. She can spend her budget on two items, X and Y. Each unit of X costs $20 and each unit o
Aleonysh [2.5K]

Answer:

Check the explanation

Step-by-step explanation:

Total utility is the overall satisfaction that a particular consumer received from consuming a given overall quantity of a good or service, To calculate the value of total utility economists utilize the following basic total utility formula: TU = U1 + MU2 + MU3

Kindly check the attached image below to see the step by step explanation to the question above.

3 0
4 years ago
(A) In some cases, neither of the two equations in the system will contain a variable with a coefficient of 1, so we must take a
Effectus [21]

Answer:

C = 17/7 or 2 3/7

D = -4/7

Step-by-step explanation:

3C+4D=5

2C+5D=2

2C = 2 - 5D

C = 1 - 2.5D

3(1 - 2.5D) + 4D = 5

3 - 7.5D + 4D = 5

-3.5D = 2

D = -4/7

C = 1 - 2.5(-4/7)

C = 1 + 10/7 = 17/7

4 0
3 years ago
Vggggggvcghbfggcchubvg
Naddika [18.5K]
The answer is your mom
3 0
3 years ago
A password is to be made from a string of five characters chosen from the lowercase letters of the alphabet and the numbers 0 th
alex41 [277]

Using the Fundamental Counting Theorem, it is found that for each case, the total number of outcomes is:

a) 60,466,176.

b) 5,961,600.

<h3>What is the Fundamental Counting Theorem?</h3>

It is a theorem that states that if there are n things, each with n_1, n_2, \cdots, n_n ways to be done, each thing independent of the other, the number of ways they can be done is:

N = n_1 \times n_2 \times \cdots \times n_n

Item a:

No restrictions, hence for each of the five characters, there are 36 outcomes, hence n_1 = \cdots = n_5 = 36.

Then, the possible number of passwords is:

N = 36^5 = 60466176

Item b:

The letters and the digits have to be alternated, hence:

  • Starting with a letter, n_1 = n_3 = n_5 = 36, n_2 = n_4 = 10.
  • Starting with a digit, n_1 = n_3 = n_5 = 10, n_2 = n_4 = 36.

Then, the possible number of passwords is:

N = 36^3 \times 10^2 + 10^3 \times 36^2 = 5961600

To learn more about the Fundamental Counting Theorem, you can take a look at brainly.com/question/24314866

5 0
3 years ago
What is the solution tot the system of equations graphed below
Slav-nsk [51]
D.
-3 = 2 (2) - 7
-3 = 4 - 7
-3 = -3

-3 = -2 -1
-3 = -3
7 0
3 years ago
Read 2 more answers
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