Answer:
Option D. (x + 4)(x + 1)
Step-by-step explanation:
From the question given above, the following data were obtained:
C = (6x + 2) L
D = (3x² + 6x + 9) L
Also, we were told that half of container C is full and one third of container D is full. Thus the volume of liquid in each container can be obtained as follow:
Volume in C = ½C
Volume in C = ½(6x + 2)
Volume in C = (3x + 1) L
Volume in D = ⅓D
Volume in D = ⅓(3x² + 6x + 9)
Volume in D = (x² + 2x + 3) L
Finally, we shall determine the total volume of liquid in the two containers. This can be obtained as follow:
Volume in C = (3x + 1) L
Volume in D = (x² + 2x + 3) L
Total volume =?
Total volume = Volume in C + Volume in D
Total volume = (3x + 1) + (x² + 2x + 3)
= 3x + 1 + x² + 2x + 3
= x² + 5x + 4
Factorise
x² + 5x + 4
x² + x + 4x + 4
x(x + 1) + 4(x + 1)
(x + 4)(x + 1)
Thus, the total volume of liquid in the two containers is (x + 4)(x + 1) L.
Answer:
Step-by-step explanation:
let 25 % copper=x kg
75 % copper=(100-x) kg
0.25 x+(100-x)*0.75=100*0.61
25x+7500-75 x=6100
-50 x=-1400
50 x=1400
5x=140
x=28
25 % of Copper=28 kg
75 % of Copper=100-28=72 kg
Answer:
0.9375sec.
Step-by-step explanation:
Using the motion formula: V= u - gt
At Max. Height, V=0, taking t=32ft/sec^2
Thus: 0 = 30 - 32t
32t = 30
t=30/32
t= 0.9375sec
Therefore,
it will take 0.9375seconds which is less than 1 second to reach maximum height, then the ball starts descending. Just after 1 sec, ball is below its maximum height and in downward motion.
