Answer:
C. Use DHCP to automatically assign addresses
Explanation:
DHCP (Dynamic Host Configuration Protocol) is a network protocol used on IP networks where a DHCP server automatically assigns an IP address and other information to each host on the network so they can communicate efficiently with other endpoints.
In addition to the IP address, DHCP also assigns the subnet mask, default gateway address, domain name server (DNS) address and other pertinent configuration parameters.
The primary reason DHCP is needed is to simplify the management of IP addresses on networks. No two hosts can have the same IP address, and configuring them manually will likely lead to errors. Even on small networks manually assigning IP addresses can be confusing, particularly with mobile devices that require IP addresses on a non-permanent basis. Also, most users aren’t technically proficient enough to locate the IP address information on a computer and assign it. Automating this process makes life easier for users and the network administrator.
Answer:
#include <stdlib.h>
#include <time.h>
#include <iostream>
using namespace std;
int main() {
srand(time(NULL));
cout << rand() % 30 << endl;
cout << rand() % 30 + 30 << endl;
cout << rand() % 30 + 60 << endl;
}
Explanation:
rand() returns a pseudo-random integral number in the range between 0 and RAND_MAX. By applying the modulo operator, you map that to the desired range (30 in your case), then you add an offset.
Answer: All of the above
Explanation: As the technology is getting improved and advanced time to time, it will put a huge impact on various sections of organization.
The advancement in the IT infrastructures will be seen by the improvement in the software,networks, data centers, hardware etc and their functioning.This will lead increase the focus of the technology towards the IT infrastructure.
Security is the feature that requires to be developed throughout the time as hacker and attackers come up with various attacks and other malicious activity to steal the confidential data and information .Thus security constantly needs to be improved and focused which will continue to happen in 21st century.
Business of organizations are becoming online and this will tend the organizations to become more indulged online business or e-business in future as it provides more benefits and vast coverage .Thus, all the options are correct.
Answer:
The answer is A4B₁₆ = 2635₁₀ = 101001001011₂
Explanation:
To convert from hexadecimal base system to binary base system, first you can do an intermediate conversion from hexadecimal to decimal using this formula:
where position of the x₁ is the rightmost digit of the number and the equivalents hexadecimal numbers to decimal:
- A = 10.
- B = 11.
- C = 12.
- D = 13.
- E = 14.
- F = 15.
A4B₁₆ = A*16²+4*16¹+B*16⁰ = 2560 + 64 + 11 = 2635₁₀
Now, you have the number transformed from hexadecimal to decimal. To convert the decimal number 2635 to binary: Divide the number repeatedly by 2, keeping track of each remainder, until we get a quotient that is equal to 0:
2635 ÷ 2 = 1317 + 1;
1317 ÷ 2 = 658 + 1;
658 ÷ 2 = 329 + 0;
329 ÷ 2 = 164 + 1;
164 ÷ 2 = 82 + 0;
82 ÷ 2 = 41 + 0;
41 ÷ 2 = 20 + 1;
20 ÷ 2 = 10 + 0;
10 ÷ 2 = 5 + 0;
5 ÷ 2 = 2 + 1;
2 ÷ 2 = 1 + 0;
1 ÷ 2 = 0 + 1;
Now, construct the integer part base 2 representation, by taking the remainders starting from the bottom of the list:
2635₁₀ = 101001001011₂
The program does not consists of any syntax error but the module contains error in logic especially while placing the condition inside if statement.
Here we are actually planning to check whether the number passed in the “value” variable is within the given lower and upper range which is passed in second and third parameter.
Solution 1:
if value<=lower AND value>=upper Then
Display “The given number is outside the specified range.”
else
Display “The given number is within the specified range.”
End if
Alternate solution:
So for that the condition needs to be value>=lower and value <=lower. so
if value > lower AND value <upper Then
Display “The given number is within the specified range.”
else
Display “The given number is within the specified range.”
